[英]Get index of the same value from two arraylist with two different sizes/length
我是Java新手,我想獲取兩個arraylist值相同的索引,但是兩個arraylist的大小/長度不同。 這是工作代碼:
List<String> new_valueString = new ArrayList<>();
List<String> new_fieldsString = new ArrayList<>();
List<String> oldValueString = new ArrayList<>();
List<String> oldFieldsString = new ArrayList<>();
if (new_fieldsString.size() != 0 && new_valueString.size() != 0) {
for (int l = 0; l < new_fieldsString.size(); l++) {
if (new_fieldsString.get(l).equalsIgnoreCase(oldFieldsString.get(l))) {
field_index = l;
if (!new_valueString.get(field_index).contains(oldValueString.get(field_index))) {
ifUpdated = true;
} else {
ifUpdated = false;
}
}
}
}
我想獲取new_fieldsString和oldFieldsString之間相同值的索引,並使用該索引來比較new_valueString和oldValueString。
您好,您需要兩個句子的第一個數組,第二個數組與短數組列表進行比較,當您發現條件為真時,別忘了打破循環,像這樣:
List<String> new_valueString = new ArrayList<>();
List<String> new_fieldsString = new ArrayList<>();
List<String> oldValueString = new ArrayList<>();
List<String> oldFieldsString = new ArrayList<>();
if (new_fieldsString.size() != 0 && new_valueString.size() != 0) {
for (int l = 0; l < new_fieldsString.size(); l++) {
for (int m = 0; m < oldFieldsString.size(); m++) {
if (new_fieldsString.get(l).equalsIgnoreCase(oldFieldsString.get(m))) {
if (!new_valueString.get(l).contains(oldValueString.get(m))) {
ifUpdated = true;
} else {
ifUpdated = false;
}
break;
}
}
}
}
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