[英]How to parse soap string in java
我已經寫了下面的代碼來解析java中的字符串,但是沒有打印出空白消息。
如何從SOAP消息中獲取特定部分並獲取其值? 我想獲取錯誤和請求中的消息。
String xml = "<?xml version='1.0' encoding='UTF-8'?>"
+ "<S:Envelope xmlns:S=\"http://schemas.xmlsoap.org/soap/envelope/\">"
+ "<S:Body>"
+ "<ns2:processResponse xmlns:ns2=\"http://ws.xxxxx.com/\">"
+ "<response><direction>response</direction>"
+ "<reference>09FG10021008111306320</reference>"
+ "<amount>0.0</amount>"
+ "<totalFailed>0</totalFailed>"
+ "<totalSuccess>0</totalSuccess>"
+ "<error>1</error>"
+ "<message>Invalid</message>"
+ "<otherReference>6360e28990c743a3b3234</otherReference>"
+ "<action>FT</action>"
+ "<openingBalance>0.0</openingBalance>"
+ "<closingBalance>0.0</closingBalance>"
+ "</response>"
+ "</ns2:processResponse>"
+ "</S:Body>"
+ "</S:Envelope>\n";
SAXBuilder builder = new SAXBuilder();
Reader in = new StringReader(xml);
Document doc = null;
Element root = null;
Element meta = null;
Element error = null;
Element status_message = null;
String status_code= "";
String message = "";
try
{
doc = builder.build(in);
root = doc.getRootElement();
meta = root.getChild("processResponse").getChild("response");
error = meta.getChild("error");
status_message = meta.getChild("message");
status_code = error.getText();
message = status_message.getText();
}catch (Exception e)
{
// do what you want
}
System.out.println("status_code: " + status_code + "\nmessage: " + message);
生成的響應是status_code:消息:
在獲取xml中的元素時,您在代碼中犯了一些錯誤。 您可以使用此代碼進行檢查,
public static void main(String[] args) {
String xml = "<?xml version='1.0' encoding='UTF-8'?>"
+ "<S:Envelope xmlns:S=\"http://schemas.xmlsoap.org/soap/envelope/\">" + "<S:Body>"
+ "<ns2:processResponse xmlns:ns2=\"http://ws.xxxxx.com/\">"
+ "<response><direction>response</direction>" + "<reference>09FG10021008111306320</reference>"
+ "<amount>0.0</amount>" + "<totalFailed>0</totalFailed>" + "<totalSuccess>0</totalSuccess>"
+ "<error>1</error>" + "<message>Invalid</message>"
+ "<otherReference>6360e28990c743a3b3234</otherReference>" + "<action>FT</action>"
+ "<openingBalance>0.0</openingBalance>" + "<closingBalance>0.0</closingBalance>" + "</response>"
+ "</ns2:processResponse>" + "</S:Body>" + "</S:Envelope>\n";
SAXBuilder builder = new SAXBuilder();
Reader in = new StringReader(xml);
Document doc = null;
Element root = null;
Element error = null;
Element status_message = null;
String status_code = "";
String message = "";
try {
doc = builder.build(in);
root = doc.getRootElement();
Element body = root.getChild("Body", Namespace.getNamespace("S", "http://schemas.xmlsoap.org/soap/envelope/"));
Element processResponse = body.getChild("processResponse", Namespace.getNamespace("ns2", "http://ws.xxxxx.com/"));
Element response = processResponse.getChild("response");
error = response.getChild("error");
status_message = response.getChild("message");
status_code = error.getText();
message = status_message.getText();
} catch (Exception e) {
e.printStackTrace();
}
System.out.println("status_code: " + status_code + "\nmessage: " + message);
}
對我來說,這給出了以下輸出,
status_code: 1
message: Invalid
將xml轉換為json,然后您可以執行任何操作。 只要記住創建一個合適的模型類來通過json映射數據
<dependency>
<groupId>org.json</groupId>
<artifactId>json</artifactId>
<version>20171018</version>
</dependency>
示例java類:
import org.json.JSONObject;
import org.json.XML;
public class Main {
public static int PRETTY_PRINT_INDENT_FACTOR = 4;
public static String TEST_XML_STRING =
"<?xml version=\"1.0\" ?><test attrib=\"moretest\">Turn this to JSON</test>";
public static void main(String[] args) {
try {
JSONObject xmlJSONObj = XML.toJSONObject(TEST_XML_STRING);
String jsonPrettyPrintString = xmlJSONObj.toString(PRETTY_PRINT_INDENT_FACTOR);
System.out.println(jsonPrettyPrintString);
} catch (JSONException je) {
System.out.println(je.toString());
}
}
}
json輸出:
{"test": {
"attrib": "moretest",
"content": "Turn this to JSON"
}}
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