Python-為未指定的輸入創建通用函數

Question

如果用戶鍵入的不是1-5，我希望該程序可以打印出一個答案，說“對不起，我無法識別該輸入”。

import time
rating=input()
if rating == '1':
    time.sleep(.5)
    print('Well, you mustve just had a bad day.')
if rating =='2':
    time.sleep(.5)
    print('Second to last means I wasnt even the best at losing...')
if rating =='3':
    time.sleep(.5)
    print('Atleast thats almost passing.')
if rating =='4':
    time.sleep(.5)
    print('Im offended.')
if rating =='5':
    time.sleep(.5)
    print('Well yeah, obviously.')

Answer 1

使用if ， elif以及else ，如果輸入的內容不是1，2，3，4，5，則代碼中的else將打印您要顯示的消息。 下面的代碼也將由於elif阻止檢查所有其他數字。 在您的代碼中，您正在檢查5 if語句中的所有數字。

import time
rating=input()
if rating == '1':
    time.sleep(.5)
    print('Well, you mustve just had a bad day.')
elif rating =='2':
    time.sleep(.5)
    print('Second to last means I wasnt even the best at losing...')
elif rating =='3':
    time.sleep(.5)
    print('Atleast thats almost passing.')
elif rating =='4':
    time.sleep(.5)
    print('Im offended.')
elif rating =='5':
    time.sleep(.5)
    print('Well yeah, obviously.')
else:
    print ('Sorry I dont recognize that input')

再次詢問用戶，直到輸入正確的號碼為止 （根據下面的評論）

while rating:
    if rating == '1':
        time.sleep(.5)
        print('Well, you mustve just had a bad day.')
        break
    elif rating =='2':
        time.sleep(.5)
        print('Second to last means I wasnt even the best at losing...')
        break
    elif rating =='3':
        time.sleep(.5)
        print('Atleast thats almost passing.')
        break
    elif rating =='4':
        time.sleep(.5)
        print('Im offended.')
        break
    elif rating =='5':
        time.sleep(.5)
        print('Well yeah, obviously.')
        break
    else:
        print ('Sorry I dont recognize that input. Enter the rating again.')
        rating=input()
        continue

輸出（第二種情況）

6
Sorry I dont recognize that input. Enter the rating again.
6
Sorry I dont recognize that input. Enter the rating again.
5
Well yeah, obviously.