[英]How to count consecutive values in Excel?
此時我有這個計算連續值的公式:
=IF(AB5=0;0;IF(OR(AND(AB4>=100;AB5>=100);AND(AB4<=-100;AB5<=-100));AC4+1;1))
基本上這樣做:
0 0
0 0
-110 1
-110 2
-110 3
-100 4
0 0
0 0
0 0
130 1
150 2
0 0
0 0
-100 1
0 0
0 0
0 0
0 0
-110 1
0 0
0 0
0 0
-220 1
-150 2
0 0
0 0
但我希望它能做到這一點:
0 0
0 0
-110 0
-110 0
-110 0
-100 4
0 0
0 0
0 0
130 0
150 2
0 0
0 0
-100 1
0 0
0 0
0 0
0 0
-110 1
0 0
0 0
0 0
-220 0
-150 2
0 0
0 0
或這個:
0 0
0 0
-110 4
-110 0
-110 0
-100 0
0 0
0 0
0 0
130 2
150 0
0 0
0 0
-100 1
0 0
0 0
0 0
0 0
-110 1
0 0
0 0
0 0
-220 2
-150 0
0 0
0 0
使這成為可能的公式是什么?
我不想添加更多列,因為文件已經很大...
僅使用公式來做這件事是最好的事情。
謝謝。
您可以嘗試這樣的匹配公式:
=IF(AND(ABS(AB5)>=100,AB4=0),MATCH(0,AB6:AB$1048576,0),0)
編輯
顯然,1,000,000個細胞的速度很慢。 不精確的匹配更快:
=IF(AND(AB5>=100,AB4=0),MATCH(0,AB6:AB$1048576,-1),IF(AND(AB5<=-100,AB4=0),MATCH(-100,AB5:AB$1048576,1),0))
討論
為什么Match在表面上這么慢,它應該只搜索前面幾個單元格來匹配? 我想知道是否因為Match將要搜索的整個范圍復制到臨時數組? 通常這可能是一個很好的策略,但在特定情況下,當匹配值接近范圍的開頭並且范圍非常大時,它是一個糟糕的策略。
另一種可能的方法是使用頻率確定最長的序列(這很快),然后使用索引來限制要搜索的范圍,例如:
=MAX(FREQUENCY(IF(ABS(A:A)>=100,ROW(A:A)),IF(A:A=0,ROW(A:A))))
然后在B1
...MATCH(0,AB6:INDEX(A:A,ROW()+B$1),0)
我不知道如何用excel解決你的問題,它可能是用一些數組公式來完成的,這會大大減慢你現在速度很慢的工作簿。 因此我寫了一個VBA版本。
在使用它之前,您應該仔細更改前三個變量的值以滿足您的需要。
將以下代碼放入模塊中 :
Option Explicit
'-- Customize BEGIN --------------------
'Read data from this column, and write to the next, e.g.
'The AB column is column 28: Read from 28 and write to 29
Public Const ciCol As Integer = 6
'The first row of data
Public Const cLoFirstRow As Long = 5
'cLoRow is an approximate value e.g. you have 200 rows of data and you
'estimate that you won't have more than a 1000 in a year, than 1000 is enough,
'if you have a million then put in a million. The smaller this number the
'faster the code.
Public Const cLoRow As Long = 1000
'-- Customize END ----------------------
Sub ConsecutiveCounting1()
''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
'-- Customize BEGIN --------------------
'The Abs function eliminates the need for a negative value variable.
Const cLoLimit As Long = 100
'-- Customize END ----------------------
''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
Dim oRng As Range
Dim loLastRow As Long
Dim loTemp As Long
Dim loF1 As Long 'Row Counter
loLastRow = Cells(Rows.Count, ciCol).End(xlUp).Row
Set oRng = Range(Cells(cLoFirstRow, ciCol), Cells(loLastRow, ciCol))
''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
loTemp = 0
For loF1 = 1 To oRng.Rows.Count
If loF1 <> oRng.Rows.Count Then
If Abs(oRng(loF1, 1)) >= cLoLimit Then
loTemp = loTemp + 1
If Abs(oRng(loF1 + 1, 1)) >= cLoLimit Then
oRng(loF1, 2) = 0
Else
oRng(loF1, 2) = loTemp
loTemp = 0
End If
Else
oRng(loF1, 2) = 0
End If
Else 'Last Value
If Abs(oRng(loF1, 1)) >= cLoLimit Then
loTemp = loTemp + 1
oRng(loF1, 2) = loTemp
Else
oRng(loF1, 2) = 0
End If
End If
Next
End Sub
然后將以下代碼放在工作表的代碼窗口中 :
Option Explicit
Private Sub Worksheet_Change(ByVal Target As Range)
Dim ColumnNumber As Long
Dim RowNumber As Long
ColumnNumber = Target.Column
RowNumber = Target.Row
If ColumnNumber <> ciCol Then Exit Sub
If RowNumber > cLoRow Then Exit Sub
ConsecutiveCounting1
End Sub
代碼會自動更改目標列中單元格的值,而在結果單元格中沒有任何公式應該使它非常快。 如果不是這種情況,可以編寫一個數組版本,這將使代碼速度提高幾十倍。
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