我想對sql oracle不同行進行分組

Question

我想按“ Facturacion”和MotorFacturaciónDrools分組。 我有這個SQL：

SELECT c.cname                   AS componente, 
       w.timeworked / 3600       AS horas, 
       Sum(w.timeworked / 3600) 
         OVER ()                 AS sum_tipo, 
       Sum(w.timeworked / 3600) 
         OVER ( 
           partition BY c.cname) AS sum_by_component 
FROM   jira.jiraissue j, 
       jira.worklog w, 
       jira.project p, 
       jira.issuetype t, 
       jira.component c, 
       jira.nodeassociation na 
WHERE  w.issueid = j.id 
       AND J.project = P.id 
       AND na.source_node_id = j.id 
       AND na.sink_node_entity = 'Component' 
       AND na.source_node_entity = 'Issue' 
       AND na.sink_node_id = c.id 
       AND t.id = j.issuetype 
       AND p.pname = 'Area Económica' 
       AND t.pname = 'Bug' 
       AND w.startdate BETWEEN To_date('01/10/2018', 'dd/mm/yyyy') AND 
                               To_date('09/10/2018', 'dd/mm/yyyy') 

結果是這樣的：

如果我將選擇內容與眾不同，則可以將其分組，但是某些行將無法捕獲。 結果是這樣的：

我想退出“ HORAS”列，僅觀看2行

Answer 1

使用不同

SELECT distinct c.cname AS componente,             
       Sum(w.timeworked / 3600) OVER ()  AS sum_tipo, 
       Sum(w.timeworked / 3600) 
     OVER ( 
       partition BY c.cname) AS sum_by_component 
FROM   jira.jiraissue j, 
       jira.worklog w, 
       jira.project p, 
       jira.issuetype t, 
       jira.component c, 
       jira.nodeassociation na 
WHERE  w.issueid = j.id 
       AND J.project = P.id 
       AND na.source_node_id = j.id 
       AND na.sink_node_entity = 'Component' 
       AND na.source_node_entity = 'Issue' 
       AND na.sink_node_id = c.id 
       AND t.id = j.issuetype 
       AND p.pname = 'Area Económica' 
       AND t.pname = 'Bug' 
       AND w.startdate BETWEEN To_date('01/10/2018', 'dd/mm/yyyy') AND 
                               To_date('09/10/2018', 'dd/mm/yyyy')

Answer 2

您已經回答了自己的問題。由於您想退出專欄文章，請從選擇中刪除以下行，並使用“ distinct”。

  w.timeworked / 3600       AS horas,