[英]How to keep only the first Character of a string before space, and all the characters after space in R
我有以下數據data.table
library(data.table)
dt <- data.table(c('Female 18 - 24', 'Male 18+', 'People 18 -54'))
我如何將其轉換為
dt <- data.table(c('F 18 - 24', 'M 18+', 'P 18 -54'))
使用regex
?
gsub('(^[A-Z])[A-Za-z]+\\s(*.)','\\1 \\2',c('Female 18 - 24', 'Male 18+', 'People 18 -54'))
[1] "F 18 - 24" "M 18+" "P 18 -54"
(^[AZ])
將第一個字母作為group1 [A-Za-z]+\\\\s
加上空格后[A-Za-z]+\\\\s
任意數量的小寫字母 (*.)
取一個空格作為group2 '\\\\1 \\\\2'
最后,返回由空格分隔的group1和group2 require(data.table)
require(stringi)
dt <- data.table(V1=c('Female 18 - 24', 'Male 18+', 'People 18 -54'))
dt[,V2:= stri_replace_first_regex(V1,"(?<=\\w)\\w+","")]
dt
V1 V2
1: Female 18 - 24 F 18 - 24
2: Male 18+ M 18+
3: People 18 -54 P 18 -54
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