[英]compare 2 files with arithmetic using awk command
我有2個文件:
文件 1
*Name|Date|id|Total*
Jimmy|03-OCT-18|BST100114262|20000
Dedi|03-OCT-18|BST100904288|10000
檔案 2
*Name|Amount*
Anton|9800
Jimmy|90000
輸出:吉米|20000|90000|1800000000
我試過了,但沒有運氣。
awk -F'|' 'NR==FNR{a[$1]=$1; next} (($1 in a) && (a[$4] >= $2 )) { print a[$4]*$2 }'
您可以嘗試以下嗎?
awk -F'|' 'NR==FNR{a[$1]=$4; next} (($1 in a) && (a[$1] <= $2 )) {$(NF+1)=a[$1]*$2;$2=a[$1] OFS $2;print}' OFS="|" File1 File2
輸出如下。
Jimmy|20000|90000|1800000000
另一個:
$ awk 'BEGIN{FS=OFS="|"}($1 in a)&&FNR>1{print $1,a[$1],$NF,a[$1]* $NF}{a[$1]=$NF}' file1 file2
輸出:
Jimmy|20000|90000|1800000000
使用Jimmies進行了一些解釋:
$ awk '
BEGIN { FS=OFS="|" } # set separators
($1 in a) && FNR>1 { # if key to hash (Jimmy) is in a excluding headers
print $1,a[$1],$NF,a[$1]* $NF # process Jimmy
# next # this excludes new Jimmy from being rehashed to a
}
{
a[$1]=$NF # ... in here where everything is hashed and the
}' file1 file2 # ... existing rehashed
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