[英]SQL Server Pivot as percentage rather than values and add a total row and column
我有代碼,這給了我一個小小的樞紐:
SELECT [U C], [M] AS EE, [F] AS LL
FROM
(SELECT [U N], f_k, [U C]
FROM [MH2]
WHERE [U C] IN ('I', 'E', 'T')) p
PIVOT (COUNT ([U N])
FOR f_k IN ([M], [F])) AS pvt
ORDER BY pvt.[U C]
輸出:
U C EE LL
E 509762 412358
I 16440 1138538
T 197 8753
但是我希望這是一個這樣的百分比,並具有總計的行和列:
U C EE LL Total
E 24.44% 19.77% 44.20%
I 0.79% 54.58% 55.37%
T 0.01% 0.42% 0.43%
Total 25.23% 74.77% 100.00%
編輯使用@ Gordon Linoff的Answer的變體解決。
SELECT COALESCE([U C], 'Total') [U C],
SUM(CASE WHEN f_k = 'F' THEN 1 ELSE 0 END) * 100.0 / cnt LL,
SUM(CASE WHEN f_k = 'M' THEN 1 ELSE 0 END) * 100.0 / cnt EE,
COUNT(*) * 100.0 / cnt Total
FROM (SELECT mh2.*, count(*) over () cnt
FROM mh2
WHERE [U C] IN ('I', 'E', 'T')
AND f_k IN ('F', 'M')) mh2
GROUP BY GROUPING SETS (([U C], cnt))
UNION ALL
SELECT 'Total', SUM(a.LL), SUM(a.EE), ROUND(SUM(a.Total),2)
FROM(
SELECT COALESCE([U C], 'Total') [U C],
SUM(CASE WHEN f_k = 'F' THEN 1 ELSE 0 END) * 100.0 / cnt LL,
SUM(CASE WHEN f_k = 'M' THEN 1 ELSE 0 END) * 100.0 / cnt EE,
COUNT(*) * 100.0 / cnt Total
FROM (SELECT mh2.*, count(*) over () cnt
FROM mh2
WHERE [U C] IN ('I', 'E', 'T')
AND f_k IN ('F', 'M')) mh2
GROUP BY GROUPING SETS (([U C], cnt))) a
我發現條件聚合要簡單得多:
select coalesce([U C], 'total') as [U C],
sum( case when fk = 'F' then 1 else 0 end) * 100.0 / cnt as EE,
sum( case when fk = 'M' then 1 else 0 end) * 100.0 / cnt as LL,
count(*) * 100.0 / cnt as total
from (select mh2.*, count(*) over () as cnt
from mh2
where [U C] in ('I', 'E', 'T') and
fk in ('F', 'M')
) mh2
group by grouping sets ( ([U C], cnt), (cnt) )
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