如何快速將 [String] 轉換為 [UInt8]？

Question

如何將我的stringArray轉換為int8Array 。 請給我任何解決方案來轉換它。 我想要以下類型的數組

let int8Array:[UInt8] = [ox55,0x55,0xff,0x01,0x0B,0x00,0x0B,0x03,0x07,0x12,0x0E,0x0C,0x10,0x09,0x12,0x0C,0x19,0x09,0xFF,0x14]

下面是我的視圖控制器：

class ViewController:UIViewController {
var checkSum:UInt8 = 0
override func viewDidLoad() {
    super.viewDidLoad()

let stringArray:[String] = ["0x55", "0x55", "0xff", "0x01", "0x0B", "0x38", "0x18", "0x31", "0x10", "0x18", "0x0E", "0x16", "0x31", "0x10", "0x18", "0x16", "0x30", "0x11", "0x18", "0x20", "0xE1"]
    var int8Array:[UInt8] = stringArray.map{ UInt8($0.dropFirst(2), radix: 16)! }
    int8Array.removeFirst()
    int8Array.removeFirst()
    int8Array.removeFirst()
    print(int8Array)
    for item in int8Array {
        checkSum = calculateCheckSum(crc: checkSum, byteValue: UInt8(item))
    }
    print(checkSum)

}

func calculateCheckSum(crc:UInt8, byteValue: UInt8) -> UInt8 {
    let generator: UInt8 = 0x1D

    var newCrc = crc ^ byteValue

    for _ in 1...8 {
        if (newCrc & 0x80 != 0) {
            newCrc = (newCrc << 1) ^ generator
        }
        else {
            newCrc <<= 1
        }
    }
    return newCrc
}

}

Answer 1

只需map這些東西，您必須刪除0x才能使UInt8(_:radix:)初始值設定項工作。

let uint8Array = stringArray.map{ UInt8($0.dropFirst(2), radix: 16)! }

Answer 2

如果這是一個選項，您可以切換它以指定UInt8數組並從中派生String數組。

let int8Array: [UInt8] = [0x55, 0x55, 0xa5, 0x3f]
var stringArray: [String] {
  return int8Array.map { String(format: "0x%02X", $0) }
}

print(stringArray)
// ["0x55", "0x55", "0xA5", "0x3F"]

Answer 3

首先獲取您的字符串數組並在其上調用map然后將其映射到[UInt8] （其中總結果將是[[UInt8]]並在結果上調用flatMap以獲取[UInt8]數組 .. 然后你可以做forEach在它上面計算你的校驗和或 w/e..

[String].init().map({
    [UInt8]($0.utf8)
}).flatMap({ $0 }).forEach({
    print($0) //Print each byte or convert to hex or w/e..
})