[英]How to combine table records with some condition in SQL table?
我在數據庫中有六張表,所有表都是相對的,想在一張表中顯示記錄。
以下是我的表格:
1) mls_stores
*----------------------------*
| store_id | store_title |
*----------------------------*
| 1001 | ajmar-jaipur |
| 1002 | dwarka-delhi |
*----------------------------*
2) mls_category
*-------------------------------------------*
| cat_no | store_id | cat_value | cat_type |
*-------------------------------------------*
| 20 | 1001 | 1 | running |
| 21 | 1001 | 4 | cycling |
| 22 | 1002 | 1 | running |
| 23 | 1002 | 2 | swmining |
*-------------------------------------------*
3) mls_points_matrix
*----------------------------------------*
| store_id | value_per_point | maxpoint |
*----------------------------------------*
| 1001 | 1 | 10 |
| 1001 | 2 | 20 |
| 1002 | 1 | 20 |
| 1002 | 4 | 30 |
*----------------------------------------*
4) mls_user
*--------------------------*
| id | store_id | name |
*--------------------------*
| 1 | 1001 | sandeep |
| 2 | 1001 | jagveer |
| 3 | 1002 | gagan |
*--------------------------*
5)bonus_points
*---------------------------------------------------*
| user_id | store_id | bonus_points | bonus_type |
*---------------------------------------------------*
| 1 | 1001 | 10 | fixed |
| 3 | 1002 | 2 | % |
*---------------------------------------------------*
6) mls_entry
*-------------------------------------------------------*
| user_id | store_id | category | distance | status |
*-------------------------------------------------------*
| 1 | 1001 | 20 | 10 | approved |
| 1 | 1001 | 21 | 40 | approved |
| 1 | 1001 | 20 | 5 | reject |
| 2 | 1001 | 21 | 40 | approved |
| 3 | 1002 | 22 | 10 | approved |
| 3 | 1002 | 23 | 20 | approved |
*-------------------------------------------------------*
現在我想要輸出如下:
*-----------------------------------------------------------------------------------*
| Name | Entries | Points Earned | Bonus Points | Total Points | Total Amount |
*-----------------------------------------------------------------------------------*
| Sandeep | running(1) | 20 | 10 | 30 | 60 |
| | cycling(1) | | | | |
*-----------------------------------------------------------------------------------*
| Jagveer | cycling(1) | 10 | 0 | 10 | 10 |
*-----------------------------------------------------------------------------------*
我正在使用以下代碼:
SELECT
u.name,
ROUND(COALESCE(t1.points, 0)) AS points,
ROUND(COALESCE(b.bonus_points, 0)) AS bonus_points,
ROUND(COALESCE(t1.points, 0) + COALESCE(b.bonus_points, 0)) AS total_points
FROM mls_user u
LEFT JOIN
(
SELECT e.user_id, e.status, SUM(e.distance / c.cat_value) AS points
FROM mls_entry e
INNER JOIN mls_category c
ON e.store_id = c.store_id AND e.category = c.cat_no
GROUP BY e.user_id
HAVING e.status='approved'
) t1
ON u.id = t1.user_id
LEFT JOIN bonus_points b
ON u.id = b.user_id
WHERE u.store_id = '1001'
ORDER BY
total_points DESC
這個 SQL 查詢給了我獲得的積分、獎勵積分和總積分,但我無法找到條目和總金額,它給了我錯誤的 Sandeep 積分計算,根據數據,一個條目被拒絕。 所以應該是 20,而不是 25。
我的總金額將用於 Sandeep 30X2(它來自點矩陣)= 60 與 jagveer 相同,jagveer 10X1 的總金額 = 10。
我在DEMO 中創建了表
試試下面:
SELECT
u.name,
ROUND(COALESCE(t1.points, 0)) AS points,
ROUND(COALESCE(b.bonus_points, 0)) AS bonus_points,
ROUND(COALESCE(t1.points, 0) + COALESCE(b.bonus_points, 0)) AS total_points,
ROUND(COALESCE(t1.points, 0) + COALESCE(b.bonus_points, 0)) * t1.countId as total_amount,
group_concat(t1.EntriesConcat) as Entries
FROM mls_user u
LEFT JOIN
(
SELECT e.user_id, e.status, SUM(e.distance / c.cat_value) AS points,
concat(c.cat_type, '(',count(e.user_id), ')' ) as EntriesConcat,
count(e.user_id) as countId -- it returns count of records according to group by part
FROM mls_entry e
INNER JOIN mls_category c
ON e.store_id = c.store_id AND e.category = c.cat_no
-- remove HAVING and use WHERE clause
WHERE e.status='approved'
GROUP BY e.user_id
) t1 ON u.id = t1.user_id
LEFT JOIN bonus_points b ON u.id = b.user_id
WHERE u.store_id = '1001'
ORDER BY total_points DESC
Group By
值
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