Python 打印語句在我的函數末尾不打印任何內容

Question

我想在我的函數結束時打印一個短語，但我想要的輸出沒有打印。 python中沒有彈出錯誤，它只是沒有打印並且表現得好像忽略了它。 wordlist 是用戶輸入的單詞列表，用於查找每個單詞在他們輸入的網站中出現的次數。 sitewordlist 是網站中的整個單詞列表。

def count(wordlist, sitewordlist):
    x = 0
    while x < len(wordlist):
       numblist = []
       wordcount = sitewordlist.count(wordlist[x])
       numblist.append(wordcount)
       x = x + 1
    final(numblist, wordlist)

def final(numblist, wordlist):    
    y = 0
    while y < len(numblist):
    print("The word" + wordlist[y] + "appears" + numblist[y] + "times.")
    y = y + 1
main()

Answer 1

問題：在你的第一個while你增加x直到它等於len(wordlist) - 你的第二個while只有在x小於len(wordlist)時才被輸入 - 這有點矛盾。

---

您可以使用collections.Counter輕松計算事物並從中獲取字典：

from collections import Counter
def count(wordlist, sitewordlist):
    data = Counter(sitewordlist)

    for w in wordlist:
        print(f"The word {w} appears {data.get(w,0)} times.")

text = """n 1066, William of Normandy introduced what, in later centuries, became referred
to as a feudal system, by which he sought the advice of a council of tenants-in-chief (a 
person who held land) and ecclesiastics before making laws. In 1215, the tenants-in-chief 
secured Magna Carta from King John, which established that the king may not levy or collect
any taxes (except the feudal taxes to which they were hitherto accustomed), save with the 
consent of his royal council, which gradually developed into a parliament. Over the 
centuries, the English Parliament progressively limited the power of the English monarchy 
which arguably culminated in the English Civil War and the trial and execution of Charles 
I in 1649. After the restoration of the monarchy under Charles II, and the subsequent 
Glorious Revolution of 1688, the supremacy of Parliament was a settled principle and all 
future English and later British sovereigns were restricted to the role of constitutional 
monarchs with limited executive authority. The Act of Union 1707 merged the English 
Parliament with the Parliament of Scotland to form the Parliament of Great Britain. 
When the Parliament of Ireland was abolished in 1801, its former members were merged 
into what was now called the Parliament of the United Kingdom. 
(quote from: https://en.wikipedia.org/wiki/Parliament_of_England)""".split()

# some cleanup
text[:] = [t.strip(".,-!?1234567890)([]{}\n") for t in text]
words = ["is","and","not","are"]

count(words,text)

輸出：

The word is appears 0 times.
The word and appears 6 times.
The word not appears 1 times.
The word are appears 0 times.

---

全櫃台：

Counter({'the': 22, 'of': 15, 'Parliament': 7, '': 6, 'and': 6, 'a': 5, 'which': 5,
'English': 5, 'in': 4, 'to': 4, 'were': 3, 'with': 3, 'was': 3, 'what': 2, 'later': 2,
'centuries': 2, 'feudal': 2, 'council': 2, 'tenants-in-chief': 2, 'taxes': 2, 'into': 2,
'limited': 2,'monarchy': 2, 'Charles': 2, 'merged': 2, 'n': 1, 'William': 1, 'Normandy': 1,
'introduced': 1, 'became': 1, 'referred': 1, 'as': 1, 'system': 1, 'by': 1, 'he': 1,
'sought': 1, 'advice': 1, 'person': 1, 'who': 1, 'held': 1, 'land': 1, 'ecclesiastics': 1, 
'before': 1, 'making': 1, 'laws': 1, 'In': 1, 'secured': 1, 'Magna': 1, 'Carta': 1,
'from': 1, 'King': 1, 'John': 1, 'established': 1, 'that': 1, 'king': 1, 'may': 1,
'not': 1, 'levy': 1, 'or': 1, 'collect': 1, 'any': 1, 'except': 1, 'they': 1, 
'hitherto': 1, 'accustomed': 1, 'save': 1, 'consent': 1, 'his': 1, 'royal': 1, 
'gradually': 1, 'developed': 1, 'parliament': 1, 'Over': 1, 'progressively': 1, 'power': 1,
'arguably': 1, 'culminated': 1, 'Civil': 1, 'War': 1, 'trial': 1, 'execution': 1, 
'I': 1, 'After': 1, 'restoration': 1, 'under': 1, 'II': 1, 'subsequent': 1, 'Glorious': 1,
'Revolution': 1, 'supremacy': 1, 'settled': 1, 'principle': 1, 'all': 1, 'future': 1, 
'British': 1, 'sovereigns': 1, 'restricted': 1, 'role': 1, 'constitutional': 1, 
'monarchs': 1, 'executive': 1, 'authority': 1, 'The': 1, 'Act': 1, 'Union': 1, 
'Scotland': 1, 'form': 1, 'Great': 1, 'Britain': 1, 'When': 1, 'Ireland': 1, 
'abolished': 1, 'its': 1, 'former': 1, 'members': 1, 'now': 1, 'called': 1, 'United': 1, 
'Kingdom': 1, 'quote': 1, 'from:': 1, 
'https://en.wikipedia.org/wiki/Parliament_of_England': 1})

---

雖然在這里不太合適。 您可以使用普通的 dict 模擬 Counter ，而像這樣：

def count_me_other(words,text):
    wordlist = words.split()
    splitted = (x.strip(".,!?") for x in text.split())
    d = {}
    it = iter(splitted)
    try:
        while it:
            c =  next(it)
            if c not in d:
                d[c]=1
            else:
                d[c]+=1
    except StopIteration:
        for w in wordlist:
            print(f"The word {w} appears {d.get(w,0)} times.")

wordlist = "A C E G I K M" 
text = "A B C D E F G A B C D E F A B C D E A B C D A B C A B A"

count_me_other(wordlist,text)

輸出：

The word A appears 7 times.
The word C appears 5 times.
The word E appears 3 times.
The word G appears 1 times.
The word I appears 0 times.
The word K appears 0 times.
The word M appears 0 times.

或者將for ...與普通 / defaultdict 結合使用：

def count_me_other_2(words,text):
    wordlist = words.split()
    splitted = (x.strip(".,!?") for x in text.split())
    d = {}
    for w in splitted:
        if w not in d:
            d[w]=1
        else:
            d[w]+=1
    for w in wordlist:
        print(f"The word {w} appears {d.get(w,0)} times.")

def count_me_other_3(words,text):
    from collections import defaultdict            
    wordlist = words.split()
    splitted = (x.strip(".,!?") for x in text.split())
    d = defaultdict(int)
    for w in splitted:
        d[w] += 1
    for w in wordlist:
        print(f"The word {w} appears {d.get(w,0)} times.")


count_me_other_2(wordlist,text)
count_me_other_3(wordlist,text)

具有相同的輸出。

Answer 2

您正在使用 while 循環來充當 for 循環，但是您在兩者中使用相同的迭代器x ，並且您沒有將其值重置為 0。 所以第二個 while 循環看到x已經等於len(wordlist) ，所以它不執行循環體。