我想用php更新數據

Question

我想用PHP更新數據。當我單擊按鈕時，頁面刷新並且不會發生更新。 如何糾正

我的代碼：文件名：Contact_settings

<form action="../netting/islem.php"  method="post" class="form-horizontal form-label-left">
<div class="form-group">
<label class="control-label col-md-3 col-sm-3 col-xs-12">Gsm Number<span class="required">*</span></label>
    <div class="col-md-6 col-sm-6 col-xs-12">
        <input type="text"  name="ayar_tel"  value="<?php echo $ayarcek['ayar_tel'] ?>" required="required" class="form-control col-md-7 col-xs-12">
    </div>

<div class="form-group">
 <div align="right" class="col-md-6 col-sm-6 col-xs-12 col-md-offset-3">
    <button type="submit" name="iletisim" class="btn btn-success right">Güncelle</button>
 </div>
  </div>

文件名：islem.php

if(isset($_POST['iletisim'])){

$ayarkaydet = $db->prepare("UPDATE ayar SET
      ayar_tel       =:ayar_tel,
      WHERE ayar_id=3
  ");
$update = $ayarkaydet->execute
(
    array(
        ':ayar_tel'       => $_POST['ayar_tel'],

    )
);

Answer 1

你的代碼有錯誤

必須是這樣

if(isset($_POST['iletisim'])){

    $ayarkaydet = $db->prepare("UPDATE ayar SET ayar_tel =:ayar_tel WHERE ayar_id=3  ");
    $update = $ayarkaydet->execute (array(':ayar_tel' => $_POST['ayar_tel']));
}

我在你的 sql where 和你的 execute 數組中刪除了兩個逗號，並為 if 語句添加了一個 close } 。