[英]Unexpected behavior from unittest.mock.patch
我下面的代碼有什么問題?
我期望assert call_func_once_with("b")
會在call_func被傳遞'a'時引發錯誤。 我確信該函數確實被調用過一次並帶有參數“ a”。
from unittest.mock import Mock, patch
def call_func(x):
pass
@patch("__main__.call_func")
def test_call_func(call_func):
call_func("a")
assert call_func.called_once_with("b")
assert call_func.called == 1
print(call_func.call_args)
test_call_func()
輸出:
call('a')
您不是第一個注意到這類斷言的奇怪事物的人(請參閱魔術嘲笑assert_call_once與assert_Called_once_with奇怪的行為 )
對於它的價值,我只能建議您嘗試創建一個從unittest.TestCase
繼承的測試類,然后使用assertEqual
方法獲取更一致的測試行為:
import unittest
from unittest.mock import patch, call
def call_func(x):
pass
class MyTests(unittest.TestCase):
@patch("__main__.call_func")
def test_call_func(self, call_func_mock):
call_func_mock("a")
# assert call_func_mock.called == 1
# assert call_func_mock.called_once_with("b")
self.assertEqual(call_func_mock.call_count, 1)
self.assertEqual(call_func_mock.call_args_list[0], call("b"))
print(call_func_mock.call_args)
unittest.main()
這給出了以下(預期)結果:
F
======================================================================
FAIL: test_call_func (__main__.MyTests)
----------------------------------------------------------------------
Traceback (most recent call last):
File "C:\Python36\lib\unittest\mock.py", line 1179, in patched
return func(*args, **keywargs)
File "C:/scratch.py", line 16, in test_call_func
self.assertEquals(call_func_mock.call_args_list[0], call("b"))
AssertionError: call('a') != call('b')
----------------------------------------------------------------------
Ran 1 test in 0.003s
FAILED (failures=1)
Process finished with exit code 1
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