打印對應的數組索引

Question

int diff = gamesA[0] - gamesB[0];
    for(int i = 0; i < gamesA.length; i++)
    {
        int y = Math.abs(gamesA[i] - gamesB[i]);
        if(y > diff)
        diff = y;
    }
    System.out.println("In quarter finals, largest deficit of schoolB was " 
+ diff + " in the" +_____+ "game.");

我正在嘗試打印出最大赤字所在數組中的索引。 不是值是什么，而是它所在的索引。 任何事情都有幫助。“____”是需要放置所需代碼的地方。

Answer 1

只需聲明變量以在循環外存儲索引

int diff = gamesA[0] - gamesB[0];
int index;
    for(int i = 0; i < gamesA.length; i++)
    {
        int y = Math.abs(gamesA[i] - gamesB[i]);
        if(y > diff)
        diff = y;
        index = i;
    }
    System.out.println("In quarter finals, largest deficit of schoolB was " + diff + " in the" + index + "game.");

Answer 2

通過以下方式：

int diff = gamesA[0] - gamesB[0];
int i; // declare it outside the loop to make it available after loop ends.
    for(i = 0; i < gamesA.length; i++)
    {
        int y = Math.abs(gamesA[i] - gamesB[i]);
        if(y > diff)
        diff = y;
    }
    System.out.println("In quarter finals, largest deficit of schoolB was " 
+ diff + " in the" +(i+1)+ "game.");
//i+1 for indexing from 1 onward .. or use just i for indexing 0 onward.

Answer 3

到目前為止，其他答案將始終打印最后一個位置。 嘗試這個：-

int diff = gamesA[0] - gamesB[0];
int pos = 0;
for (int i = 0; i < gamesA.length; i++) {
    int y = Math.abs(gamesA[i] - gamesB[i]);
    if (y > diff) {
        diff = y;
        pos = i;
    }
}
System.out.println("In quarter finals, largest deficit of schoolB was "
        + diff + " in the" + pos + "game.");