[英]Nested for loops to iterate between two strings
我想使用for循環,遍歷每個字符串並依次輸出每個字符。
String a = "apple";
String b = "class";
for (int i = 0; i < a.length() ; i++) { // - 1 because 0 = 1
System.out.print(a.charAt(i));
for (int j = 0; j < b.length(); j ++) {
System.out.print(b.charAt(j));
}
}
我正在努力與內循環。
目前,我的輸出如下:
AClasspClasspClasslClasseClass
但是,我想實現以下目標:
acplpalses
擴展問題:
如何反向輸出一個字符串,而正常輸出另一個字符串呢?
當前嘗試:
for (int i = a.length() - 1; i >= 0; i--) {
System.out.println(a.charAt(i));
for (int j = 0; j < b.length(); j ++) {
System.out.println(b.charAt(j));
}
}
但是,這只是簡單地以上述方式輸出,只是以與前面相同的格式以相反的順序輸出“ Apple”:
eclasslclasspclasspclassaclass
您不需要兩個循環,因為兩個Strings
索引相同
相同順序:
簡單的相同大小的情況:
for (int i = 0; i < a.length(); i++) { System.out.print(a.charAt(i)); System.out.print(b.charAt(i)); }
復雜的大小不同的案例:
int minLength = Math.min(a.length(), b.length()); for (int i = 0; i < minLength; i++) { System.out.print(a.charAt(i)); System.out.print(b.charAt(i)); } System.out.print(a.substring(minLength)); // prints the remaining if 'a' is longer System.out.print(b.substring(minLength)); // prints the remaining if 'b' is longer
不同的順序:
簡單的相同大小的情況:
for (int i = 0; i < a.length(); i++) { System.out.print(a.charAt(i)); System.out.print(b.charAt(b.length() - i - 1)); }
復雜的大小不同的案例:
int minLength = Math.min(a.length(), b.length()); for (int i = 0; i < minLength; i++) { System.out.print(a.charAt(i)); System.out.print(b.charAt(b.length() - i - 1)); } System.out.print(a.substring(minLength)); System.out.print(new StringBuilder(b).reverse().substring(minLength));
使用Java 8流的另一種解決方案:
System.out.println(
IntStream.range(0, Math.min(a.length(), b.length()))
.mapToObj(i -> "" + a.charAt(i) + b.charAt(i))
.collect(Collectors.joining(""))
);
對於擴展問題-假設兩個字符串的大小相同
for (int i = 0; i < a.length(); i++) {
System.out.print(a.charAt(a.length()-1-i));
System.out.print(b.charAt(i));
}
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