[英]pointer pointer string (char **) from user input in C
我是C語言的新手,出於我需要的目的,我似乎在指針指針char上找不到太多內容。 這是我的簡化代碼:
int total, tempX = 0;
printf("Input total people:\n");fflush(stdout);
scanf("%d",&total);
char **nAmer = (char**) malloc(total* sizeof(char));
double *nUmer = (double*) malloc(total* sizeof(double));;
printf("input their name and number:\n");fflush(stdout);
for (tempX = 0;tempX < total; tempX++){
scanf("%20s %lf", *nAmer + tempX, nUmer + tempX); //I know it's (either) this
}
printf("Let me read that back:\n");
for (tempX = 0; tempX < total; tempX++){
printf("Name: %s Number: %lf\n",*(nAmer + tempX), *(nUmer + tempX)); //andor this
}
我不確定在獲取用戶輸入時指針指標char的正確格式是什么。 如您所見,我正在嘗試獲取人們的姓名及其號碼的列表。 我知道數組,矩陣和類似的東西很容易,但是它只能是一個指針指針。 謝謝!
如果要存儲N個字符串(每個字符串最多20個字符),則不僅需要分配用於指向字符串的指針的空間,還需要分配用於存儲字符串本身的空間。 這是一個例子:
#include <stdlib.h>
#include <stdio.h>
int main(int argc, char ** argv)
{
int total, tempX = 0;
printf("Input total people:\n");fflush(stdout);
scanf("%d",&total);
printf("You entered: %i\n", total);
// note: changed to total*sizeof(char*) since we need to allocate (total) char*'s, not just (total) chars.
char **nAmer = (char**) malloc(total * sizeof(char*));
for (tempX=0; tempX<total; tempX++)
{
nAmer[tempX] = malloc(21); // for each string, allocate space for 20 chars plus 1 for a NUL-terminator byte
}
double *nUmer = (double*) malloc(total* sizeof(double));;
printf("input their name and number:\n");fflush(stdout);
for (tempX = 0; tempX<total; tempX++){
scanf("%20s %lf", nAmer[tempX], &nUmer[tempX]);
}
printf("Let me read that back:\n");
for (tempX = 0; tempX<total; tempX++){
printf("Name: %s Number: %lf\n", nAmer[tempX], nUmer[tempX]);
}
// Finally free all the things we allocated
// This isn't so important in this toy program, since we're about
// to exit anyway, but in a real program you'd need to do this to
// avoid memory leaks
for (tempX=0; tempX<total; tempX++)
{
free(nAmer[tempX]);
}
free(nAmer);
free(nUmer);
}
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.