![](/img/trans.png)
[英]java.lang.IllegalStateException: Cannot get a numeric value from a text cell
[英]Getting this error: Message: java.lang.IllegalStateException: Cannot get a text value from a numeric cell
import com.itko.lisa.vse.stateful.model.TransientResponse;
import com.itko.lisa.vse.stateful.model.Response;
import com.itko.util.ParameterList;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.util.Iterator;
import java.lang.String;
import org.apache.log4j.*;
import groovy.util.logging.*;
import org.apache.poi.xssf.usermodel.XSSFCell;
import org.apache.poi.xssf.usermodel.XSSFRow;
import org.apache.poi.xssf.usermodel.XSSFSheet;
import org.apache.poi.xssf.usermodel.XSSFWorkbook;
FileInputStream fileInputStream = new FileInputStream("C:/Softwares/LISA/CBO_CurrentBalance1/Data/BalanceReport.xlsx");
//FileInputStream fileInputStream = new FileInputStream("/home/lisa-user/Data/CBOPayment.xlsx");
XSSFWorkbook workbook = new XSSFWorkbook(fileInputStream)
XSSFSheet sheet = workbook.getSheet("Sheet1");
XSSFRow row;
XSSFCell cell;
Iterator rows = sheet.rowIterator();
while (rows.hasNext()) {
row = (XSSFRow) rows.next();
Iterator cells = row.cellIterator();
AccountNumber1 = testExec.getStateObject("AccountNumber1")
AccountNumber2 = testExec.getStateObject("AccountNumber2")
if (AccountNumber1 == cells.next().getStringCellValue()) {
if(cells.hasNext()) {
Balance = cells.next().getNumericCellValue();
testExec.setStateValue("Balance1", Balance);
}
}
if (AccountNumber2 == cells.next().getStringCellValue()) {
if (cells.hasNext()) {
Balance = cells.next().getNumericCellValue();
testExec.setStateValue("Balance2", Balance);
}
}
}
您需要這樣的東西: 不要與命名約定混淆,因為這是我的代碼之一。 問題是
DataFormatter fmt = new DataFormatter(); String _charges = fmt.formatCellValue(sheet.getRow(45).getCell(CellReference.convertColStringToIndex("D")));
您正在做的是嘗試從工作表中獲取一個數值,而該數值另存為字符串,因此您需要先將其轉換為字符串,然后才能使用它。 我粘貼的代碼不是確切的解決方案,但希望您能得到有關該解決方案的提示。
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.