[英]JSON Object with variables into PostgreSQL
我有以下功能:
create or replace function something(id integer)
RETURNS INTEGER
language plpgsql
as $$
DECLARE
name varchar;
email varchar;
route varchar;
now timestamp;
BEGIN
now = current_timestamp;
SELECT apd.apd_nome, apd.apd_email, CAST(r.rota_params->>'url_completa' as varchar) into name, email, route FROM avise_produto_disponivel apd
inner join produto p on apd.pro_id = p.pro_id
inner join produto_div div on p.pro_id = div.pro_id
inner join produto_oferta_div pod on div.pod_id = pod.pod_id
inner join produto_oferta po on po.ofe_id = pod.ofe_id
inner join rotas r on CAST(r.rota_params->>'oferta_id' as integer) = po.ofe_id
where apd.pro_id = $1;
DELETE FROM avise_produto_disponivel where pro_id = $1;
rota = CONCAT('https://www.something.com/', route);
INSERT INTO comunicacao (cot_id, com_para, com_assunto, com_data_criado, com_parametros, com_para_nome, cos_id, com_de) VALUES (1, email, 'Produto Chegou', now, '{"NOME": name, "URL": route}', name, 1, 'correio');
return 1;
END;
$$ ;
但是當我嘗試執行時,出現以下錯誤:
[22P02] ERROR: invalid input syntax for type json Detalhe: Token "nome" is invalid. Where: JSON data, line 1: {"NOME": name... PL/pgSQL function avise_me(integer) line 18 at SQL statement
提前致謝。
您可以通過castin測試JSON語法的使用情況,測試
SELECT '{"NOME": "JOÃO", "URL": "http://rota.com.br"}'::json;
它是一個轉換為JSON的字符串表示形式...並不是您所需要的。 嘗試在INSERT INTO comunicacao
使用以下內容
json_build_object('nome', name, 'URL', route)
參見https://www.postgresql.org/docs/current/functions-json.html
PS1:似乎在初始“ SELECT INTO”處也存在錯誤。
PS2:我更喜歡在幾乎所有應用程序中使用JSONb而不是JSON。
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