根據其他哈希數組的鍵值更新一個哈希數組

Question

我有兩個哈希數組。 我正在嘗試從醫生陣列哈希中刪除記錄，其中，doctor_patient_id不存在於patient_and_doctor哈希數組的doctor_patient_id數組中。

doctor = [
  { :doctor_patient_id=>"abc",
    :doctor_id=>"d1"
  },
  { :doctor_patient_id=>"def",
    :doctor_id=>"d2"
  },
  { :doctor_patient_id=>"ghi",
    :doctor_id=>"d3"
  }
]

patient_and_doctor = [
  { :patient_id=>"11e8f37477ab7028a66b210b9699def9",
    :doctor_patient_id=>[ "def", "zkj", "cps" ]
  },
  { :patient_id=>"11e8f37481fabfe68630f5da2e22dceb",
    :doctor_patient_id=>[ "uio", "ghi", "jkk" ]
  }
]

預期產量是：

doctor = [
      { :doctor_patient_id=>"def",
        :doctor_id=>”d2”
      },
      { :doctor_patient_id=>"ghi",
        :doctor_id=>”d3”
      }
    ]

我試着做下面的事，但沒有運氣，

patient_and_doctor.each do |dp|
  data = doctor.map {|d| d[:doctor_patient_id].include? 
   dp[:doctor_patient_id] }
end

我怎樣才能實現這一目標？

Answer 1

valid_ids = patient_and_doctor.flat_map { |h| h[:doctor_patient_id] }
# => ["def", "zkj", "cps", "uio", "ghi", "jkk"]

doctor.select { |h| valid_ids.include? h[:doctor_patient_id] }
# => [{:doctor_patient_id=>"def", :doctor_id=>"d2"},
#     {:doctor_patient_id=>"ghi", :doctor_id=>"d3"}]

使用select! 而不是select如果你想改變你的doctor數組而不是返回一個新的。

Answer 2

以下可以獲得必要的答案，

doctor.select { |x|  patient_and_doctor.map { |x| x[:doctor_patient_id] }.flatten.include?(x[:doctor_patient_id]) }