如何使用indexOf（）檢查數組中的字符串是否部分匹配另一個數組中的字符串？

Question

我有一個過濾特定項目表的功能。 在我的應用程序中，我有許多具有不同過濾器的表，因此我編寫了一個函數，可以用動態數據過濾表。 一些過濾器使用輸入，用戶必須在其中輸入查詢。 如果用戶查詢僅部分匹配表數組之一中的字符串，則表不會返回預期結果。

例如

filterArr = [null, null, "246", null]
TableFilter = [
    {"name": Matthew Shapiro", "claim_number":"2469135-6", "type": "Medical", "date": "05/04/2018", "doctor": "John Smith", "hospital": "University Hospital"},
    {"name": "John Connor", "claim_number": "1352460-2", "type": "Medical", "date": "01/01/2018", "doctor": "John Smith", "hospital": "University Hospital"},
    {"name": "Sam Heist", "claim_number": "1270120-9", "type": "Medical", "date": "02/11/2018", "doctor": "William Rodgers", "hospital":  "Springfield Hospital"}
]

在此示例中，即使在“ 2469135-6”和“ 1352460-2”中找到246，該表也不會返回前兩行。 如果我將過濾器中的查詢更新為任意一個數字的完整字符串，它將得到。

如果filterArr中的字符串與TableFilter [i]中的字符串部分匹配，如何更新函數以返回適當的TableFilter？

以下是我的功能以及其中一張桌子的屏幕截圖。

let rowArr = []
let filteredResults = []

this.rows.map(element => {
    rowArr = Object.values(element); // Object.values of each row
    rowArr.filter(e => { 
        if (rowArr.indexOf(filterArr) !== -1) {
            // check for substring match. Currently not working
            console.log('match');
        }

        if (filterArr.includes(e)) { // check if filter has value that matches row
            filteredResults.push(element);
            this.rows = filteredResults;
        }
    })
})

Answer 1

您要為某些字段值包含某些 filterArray值的行過濾 TableFilter數組。

 var filterArr = [null, null, "246", null]; var TableFilter = [ {"name": "Matthew Shapiro", "claim_number":"2469135-6", "type": "Medical", "date": "05/04/2018", "doctor": "John Smith", "hospital": "University Hospital"}, {"name": "John Connor", "claim_number": "1352460-2", "type": "Medical", "date": "01/01/2018", "doctor": "John Smith", "hospital": "University Hospital"}, {"name": "Sam Heist", "claim_number": "1270120-9", "type": "Medical", "date": "02/11/2018", "doctor": "William Rodgers", "hospital": "Springfield Hospital"} ]; var foundResults = TableFilter.filter(row => { return Object.keys(row).some(fieldName => { return filterArr.some(filt => { return row[fieldName].indexOf(filt) > -1; }); }); }); console.log(foundResults);