迭代每一行並獲取計數php mysql

Question

我在mysql中有一行

Uid  campid  type
1    100     Type1
1    100     Type1
1    200     Type1

我需要獲取每個Campid的每個Type1的數量

ie）對於Type1的Campid 100-計數= 2

對於Type1的Campid 200-計數= 1

下面我得到我不想要的所有坎皮德的總數。

$Impressionarr = [];
$imp_qry = "select count(*) as ImpressionCount from ClicksAndImpressions where Uid = 101655 and CampaignID = 109 and Type='Impression' ;";
$impData = $this->getClicksAndImpressionsTable()->CustomQuery($imp_qry);

if($impData[0]['ImpressionCount'] != '' || $impData[0]['ImpressionCount'] !=NULL ){
                $impr_update = "UPDATE ClicksAndImpressions SET ImpressionCount = ". $impData[0]['ImpressionCount'] ." where Uid = 101655 and CampaignID =109 and Type='Impression' ;";
                $impqryexecute= $this->getClicksAndImpressionsTable()->CustomUpdate($impr_update);

                foreach($impData as $key=>$data2)
                {
                    $data2['ImpressionCount'];
                    $Impressionarr[] = $data2; 
                }

            }else{
                return array("errstr" => "success.", "success" => 0, "Campaigns" => "No Impression Counts");
            }


public function CustomQuery($id) {
  $sql = $id;
  foreach (($this->tableGateway->getAdapter()->driver->getConnection()->execute($sql)) as $row){
        $results[] = $row;
    }
    return $results;
}

Answer 1

select count(uid) as total, type from ClicksAndImpressions  group by campid  

嘗試以上查詢