[英]I/O-TxtFile Line Distance Program | JAVA
我正在嘗試編寫一個通過.txt輸入文件循環的實驗室/程序。 以字符串形式讀取整行數據,然后將該字符串拆分為以空格分隔的數組。 如果結果數組中有4個項目,並且每個項目都是有效的double,我希望它確定點之間的距離並將返回信息返回到單獨的output.txt文件。
我遇到的問題是無法通過if語句if(testDoubleLow()){
如果我將其編寫為if(testDoubleLow(item1,0)){
,則無法讓x1,x2,y1,y2全部運行那么它只會驗證x1或aka txt行上的第一個輸入?
{我的密碼}
import java.io.*;
import java.util.Scanner;
public class RLabs {
public static void main(String[] args) throws FileNotFoundException {
double dealtaX, deltaY, distance, x1, y1, x2, y2;
String Line, item1, item2, item3, item4;
String[] Sect;
Scanner inFile;
PrintWriter outFile;
System.out.println("I/O File Line Distance Program Starting. Opening file...");
System.out.println("Please ensure data is entered per line in the format of (X1 Y1 X2 Y2).");
inFile = new Scanner(new File("input.txt"));
outFile = new PrintWriter(new File("countresults.txt"));
while (inFile.hasNext()) {
Line = inFile.nextLine();
Sect = Line.split(" ");
if (Sect.length == 4) {
item1 = Sect[0];
item2 = Sect[1];
item3 = Sect[2];
item4 = Sect[3];
outFile.printf(Line);
if (testDoubleLow()) {
x1 = Double.parseDouble(item1);
y1 = Double.parseDouble(item2);
x2 = Double.parseDouble(item3);
y2 = Double.parseDouble(item4);
dealtaX = (x2 - x1);
deltaY = (y2 - y1);
distance = Math.sqrt(Math.pow(deltaY, 2) + Math.pow(dealtaX, 2));
outFile.printf(" The distance between (%1.1f,%1.1f) and (%1.1f,%1.1f) is %1.1f\n",
x1, y1, x2, y2, distance);
}
} else {
outFile.println("Line did not have 4 item(s)");
}
}
outFile.close();
inFile.close();
System.out.println("Done...");
}
private static boolean testDoubleLow(String token, double l) {
if (testDouble(token)) {
double num = Double.parseDouble(token);
if (num > l) {
return true;
}
}
return false;
}
private static boolean testDouble(String s) {
try {
Double.parseDouble(s);
return true;
} catch (Exception e) {
return false;
}
}
}
import java.io.*;
import java.util.Scanner;
public class RLabs {
public static void main(String[] args) throws FileNotFoundException {
double dealtaX, deltaY, distance,x1, y1, x2, y2;
String Line, item1, item2, item3, item4;
String[] Sect;
Scanner inFile;
PrintWriter outFile;
System.out.println("I/O File Line Distance Program Starting. Opening file...");
System.out.println("Please ensure data is entered per line in the format of (X1 Y1 X2 Y2).");
inFile = new Scanner(new File("input.txt"));
outFile = new PrintWriter(new File("countresults.txt"));
while(inFile.hasNext()){
Line = inFile.nextLine();
Sect = Line.split(" ");
if(Sect.length == 4) {
item1 = Sect[0];
item2 = Sect[1];
item3 = Sect[2];
item4 = Sect[3];
if(testDoubleLow(item1,0)&&(testDoubleLow(item2,0)&&(testDoubleLow(item3,0)&&(testDoubleLow(item4,0))))){
x1 = Double.parseDouble(item1);
y1 = Double.parseDouble(item2);
x2 = Double.parseDouble(item3);
y2 = Double.parseDouble(item4);
dealtaX = (x2-x1);
deltaY = (y2-y1);
distance = Math.sqrt(Math.pow(deltaY,2)+ Math.pow(dealtaX,2));
outFile.printf(Line);
outFile.printf(" The distance between (%1.1f,%1.1f) and (%1.1f,%1.1f) is %1.1f\n", x1,y1,x2,y2,distance);
}
else {
outFile.println("Line did not correct data");
}
}
else {
outFile.println("Line did not have 4 item(s)");
}
}
outFile.close();
inFile.close();
System.out.println("Done...");
}
private static boolean testDoubleLow(String token, double l){
if(testDouble(token)) {
double num = Double.parseDouble(token);
if(num > l ) {
return true;
}
}
return false;
}
private static boolean testDouble(String s) {
try {
Double.parseDouble(s);
return true;
}
catch(Exception e) {
return false;
}
}
}
我不知道這是否是一個正確的答案,或者只是一個臨時的路過,但我希望這可能是對的嗎? if(testDoubleLow(item1,0)&&(testDoubleLow(item2,0)&&(testDoubleLow(item3,0)&&(testDoubleLow(item4,0))))){
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