[英]Remove if array contains string from another array
因此,我們的想法是從一個數組中刪除其他數組的編號列表,但僅刪除第一個數組,解決該問題的任何幫助將不勝感激。
$my_array = array("Sandra Loor,593984076233","Adrian,593998016010","Lucas,593999843424");
function myFilter($string) {
$to_remove = array("593984076233","593998016010");
foreach($to_remove as $remove) {
return strpos($string, $remove) === false;
}
}
$newArray = array_filter($my_array, 'myFilter');
foreach ($newArray as $val){
echo $val.'<br>';
}
問題是您的過濾器將始終從循環的第一次迭代return
。 相反,如果找到條目,它將返回false,並且在循環結束時將返回true(即完全找不到)...
function myFilter($string) {
$to_remove = array("593984076233","593998016010");
foreach($to_remove as $remove) {
if ( strpos($string, $remove) !== false )
return false;
}
return true;
}
另一種方法是使用preg_grep在數組中搜索要刪除的項目,然后使用array_diff刪除它們。
$my_array = array("Sandra Loor,593984076233","Adrian,593998016010","Lucas,593999843424");
$to_remove = array("593984076233","593998016010");
$to_remove = "/" . implode("|", $to_remove) . "/";
$match = preg_grep($to_remove, $my_array);
$filtered = array_diff($my_array, $match);
var_dump($filtered);
// Lucas,593999843424
您也可以將其捆扎成一個襯板,如下所示:
$my_array = array("Sandra Loor,593984076233","Adrian,593998016010","Lucas,593999843424");
$to_remove = array("593984076233","593998016010");
$filtered = array_diff($my_array, preg_grep("/" . implode("|", $to_remove) . "/", $my_array));
var_dump($filtered);
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