如何使用javascript獲取字符串中重復的DYNAMIC html標簽之間的字符串？ （沒有正則表達式，除非它是唯一的方法！）

Question

作為解釋的一種方式，我沒有發布我擁有的巨大字符串（其中包含動態 html 標簽並使用唯一 id 自動生成）。 我想使用任何 excep Regex來獲取每個標記之間的文本"<p class=partial_entry>... comment...</p>" ，在我的情況下，通過獲取 20 個重復標記的字符串外部HTML。 我在下面有一個例子：

var str = "<div class=prw_rup prw_reviews_text_summary_hsx data-prwidget-name=reviews_text_summary_hsx data-prwidget-init=handlers>
<div class=entry><p class=partial_entry>You have to try their special sushi rolls like acevichado or patrullero. They have great selections of sushi and other dishes.</p>
</div></div><div class=prw_rup prw_reviews_text_summary_hsx data-prwidget-name=reviews_text_summary_hsx data-prwidget-init=handlers><div class=entry><p class=partial_entry>
All you can eat sushi fir $20 ($24 including tax)! Christian, our server, was wonderful and attentive.
</p></div></div><div class=prw_rup prw_reviews_text_summary_hsx data-prwidget-name=reviews_text_summary_hsx data-prwidget-init=handlers>
<div class=entry><p class=partial_entry>The place was good, also the waiters, but definitely sushi is the best in town 
for my opinion, even with the few options of it in this place. I will be there soon again.</p></div></div>";

我想要的是我在示例中的 3 條評論，所以我使用了 20 條代碼：

- You have to try their special sushi rolls like acevichado or patrullero. They have great selections of sushi and other dishes.

- All you can eat sushi fir $20 ($24 including tax)! Christian, our server, was wonderful and attentive.

- The place was good, also the waiters, but definitely sushi is the best in town for my opinion, even with the few options of it in this place. I will be there soon again.

我嘗試制作自己的代碼，但中間的文本或標簽沒有被刪除，因為它檢測到我預設的標簽，例如： "THE WHOLE STRING AFTER THE TAG IM LOOKING FOR + <p class=partial_entry>... comment...</p>"整個"THE WHOLE STRING AFTER THE TAG IM LOOKING FOR + <p class=partial_entry>... comment...</p>"而我只想要...comment...部分。

我制作的代碼如下：

var temp = "<p class=partial_entry";
    var res = str.split('>');
    var res2 = res.indexOf(temp) + 1;
    var resultado = null;
    
     if (res2 < res.length && res2 != -1) {
         resultado = res[ res2 ]; // gets the next one
    }
    
    alert(resultado);

Answer 1

這非常簡單，假設評論將始終包含在具有partial_entry類的節點中：

var commentNodes = document.getElementsByClassName('partial_entry');
var comments = [];
for (var i = 0; i < commentNodes.length; i++) {
  comments.push(commentNodes[i].innerText);
}

Answer 2

您可以使用 for 循環遍歷每個字符直到它看到，然后存儲每個字符直到它看到

這可能不是最好的方法，如果 p 中有其他標簽，它也不會起作用。 但它有效。

 var text = "<p class=partial_entry>This text should show up</p>" var seenBeginTag = false; var seenEndTag = false; var output = []; for (var i = 0; i < text.length; i++) { if (seenBeginTag && seenEndTag) { if (text[i] == '<') { seenBeginTag = false; seenEndTag = false; } else { output.push(text[i]); } } else if (seenBeginTag) { if (text[i] == '>') { seenEndTag = true; } } else if (text[i] == '<') { if (text[i+1] == 'p') { seenBeginTag = true; } } } console.log(output.join(''));