如何在Codeigniter查詢中找到非ASCII字符？

Question

以下查詢我已經嘗試過mysql並且工作正常，但我需要以codeigniter活動記錄類的形式。

SELECT name FROM tblmarkets_football WHERE name <> CONVERT(name USING ASCII);

我嘗試過類似的東西，但它不起作用我得到500錯誤.....

$wherestr = 'tblmarkets_football.name <>'. CONVERT(tblmarkets_football.name. ' USING ASCII');
$this->db->select('*');
$this->db->from('tblmarkets_football');
$this->db->join('tblmarkets','tblmarkets.id = tblmarkets_football.market_id','left');
$this->db->where($wherestr);

Answer 1

Active Record允許在WHERE使用自定義字符串，前提是您在條件中傳遞了NULL值，在轉義時傳遞了FALSE 。

$wherestr = 
   'tblmarkets_football.name <> CONVERT(tblmarkets_football.name USING ASCII)' );
$this->db->where( $wherestr, NULL, FALSE );

請參閱->where()方法上的文檔： https ： //www.codeigniter.com/userguide3/database/query_builder.html#looking-for-specific-data