驗證數組內屬性對象的值

Question

我有以下數組：

arrayObject = [
    { type: "one" },
    { type: "two" },
    { type: "other" },
];

而且我還有以下帶有值的數組：

types = [
    "one",
    "other"
];

我需要驗證這兩個值是否存在，如果不存在，則必須阻止它們在流程中前進，目前我正在做的是：

arrayObject.filter(object => types.includes(object.type))

並且此代碼在不存在時返回我，但在一個或另一個不存在時也返回我，但是我需要知道這兩個是否存在，這對我不起作用

Answer 1

使用every

if (types.every(t => arrayObject.findIndex(a => a.type === t) > -1))

Answer 2

您還可以將Array.from與Array.every和Array.includes ：

 const arrayObject = [{ type: "one" }, { type: "two" }, { type: "other" }]; const types = ["one", "other"]; const result = types.every(t => Array.from(arrayObject, x=> x.type).includes(t)) console.log(result) 

您也可以使用Array.some獲得更簡潔的解決方案：

 const arrayObject = [{ type: "one" }, { type: "two" }, { type: "other" }]; const types = ["one", "other"]; const result = types.every(t => arrayObject.some(x => x.type === t)) console.log(result) 

並且由於您有lodash標簽：

 const arrayObject = [{ type: "one" }, { type: "two" }, { type: "other" }]; const types = ["one", "other"]; const result = _.every(types, x => _.some(arrayObject, {type: x})) console.log(result) 

 <script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.10/lodash.min.js"></script> 

Answer 3

使用_.map()從arrayObject中_.map() type 。 使用_.intersection() ，並將結果長度與types數組的長度進行比較：

 const arrayObject = [{"type":"one"},{"type":"two"},{"type":"other"}]; const types = ["one","other"]; const result = _.eq( _.intersection(types, _.map(arrayObject, 'type')).length , types.length); console.log(result); 

 <script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.11/lodash.min.js"></script>