為什么“找不到帳戶”行不起作用？ 還是編碼的初學者，並嘗試過if和else語句

Question

基本銀行應用

print('------------------------------------------------')
print("Welcome to Anthony's Bank App! ")
print('------------------------------------------------')
Names=[]
Accounts=[]
Balance=[]
def popArray():
    print("---------------------------------------------")
    for aNumber in range (5):
        AccountName = input("Enter a name for the account (or enter E to go to menu):" )
        if AccountName == "E" or AccountName == "e":
            choicesMenu()
        else:
            Names.append(AccountName)
        AccountID = input("Enter account ID number: ")
        Accounts.append(AccountID)
        BalanceVal = (int(input("Enter an account balance: ")))
        Balance.append(BalanceVal)
    choicesMenu()

def searchArray():
    position = 0
    accountIDstr=input("Please enter your account ID number: ")
    for aNumber in range(10):
        if (accountIDstr == Accounts[position]):
            break
        if (accountIDstr != Accounts[position]):
            position += 1
    if (accountIDstr == Accounts[position]):
        print("---------------------------------------------")
        print("Account Holder: ", Names[position])
        print("Balance: $", Balance[position])
        choicesMenu()
    else:
        print("Account not found. Please try again...")
        choicesMenu()

def depArray():
    position = 0
    accountIDstr=input("Please enter your account ID number: ")
    for aNumber in range(5):
        if (accountIDstr == Accounts[position]):
            break
        if (accountIDstr != Accounts[position]):
            position += 1
    balanceAmt = Balance[position]
    print("---------------------------------------------")
    print("Account Holder: ", Names[position])
    print("Balance: $", balanceAmt)
    depositAmt=int(input("Enter deposit amount: "))
    NewBalance = int(balanceAmt) + depositAmt
    total = NewBalance
    Balance[position]=total
    print("---------------------------------------------")
    print("New Balance: $", Balance[position])
    choicesMenu()

def wdrawArray():
    position=0
    accountIDstr=input("Please enter your account ID number: ")
    for aNumber in range(5):
        if (accountIDstr == Accounts[position]):
            break
        if (accountIDstr != Accounts[position]):
            position += 1
    balanceAmt = Balance[position]
    balanceVal = int(balanceAmt)
    print("---------------------------------------------")
    print("Account Holder: ", Names[position])
    print("Balance: $", balanceVal)
    withdrawAmt=int(input("Enter withdraw amount: "))
    if withdrawAmt > balanceVal:
        print("------------------------------------------------")
        print("Insufficient Funds. Try again...")
        choicesMenu()
    else:
        NewBalance = balanceVal - withdrawAmt
        total = NewBalance
        Balance[position]=total
        print("---------------------------------------------")
        print("New Balance: $", Balance[position])
        choicesMenu()

def exitArray():
    print("------------------------------------------------")
    print("Thank you for using Anthony's Bank App. Have a nice day! ")
    print(":)")
    quit()

def choicesMenu():
    print("------------------------------------------------")
    print("Enter P to populate accounts.")
    print("Enter S to search for an account.")
    print("Enter E to exit the app.")
    print("Enter D to deposit funds into an account.")
    print("Enter W to withdraw funds from an account.")
    inputStr = input("Please pick a choice: ")
    if inputStr == "P" or inputStr == "p":
        popArray()
    if inputStr == "S" or inputStr == "s":
        searchArray()
    if inputStr == "E" or inputStr == "e":
        exitArray()
    if inputStr == "D" or inputStr == "d":
        depArray()
    if inputStr == "W" or inputStr == "w":
        wdrawArray()
    else:
        print("Invalid choice. Try again...")
        choicesMenu()
choicesMenu()

該區域是錯誤的區域

填充（創建）帳戶，搜索帳戶並輸入不在“帳戶”列表中的帳戶ID后，它應顯示“找不到帳戶。請重試”。 但是，當我運行它時，它顯示一個錯誤而不是顯示提示。 有什么建議或我做錯了什么嗎？ 我目前正在學習python。

def searchArray():
    position = 0
    accountIDstr=input("Please enter your account ID number: ")
    for aNumber in range(10):
        if (accountIDstr == Accounts[position]):
            break
        if (accountIDstr != Accounts[position]):
            position += 1
    if (accountIDstr == Accounts[position]):
        print("---------------------------------------------")
        print("Account Holder: ", Names[position])
        print("Balance: $", Balance[position])
        choicesMenu()
    else:
        print("Account not found. Please try again...")
        choicesMenu()

Answer 1

由於您尚未提供錯誤，因此我將猜測錯誤是什么：

在searchArray函數中，您最多可以將position增加10次。 如果你沒有在10個賬戶Accounts和你正在尋找一個accountIDstr不在Accounts ，你會嘗試索引列表的范圍之外。

---

短期修復是這樣說的：

for aNumber in range(len(Accounts)):

但我強烈建議您研究一些更好的Pythonic解決方案。 請參閱以下一個可能的起點。

---

長期：

盡管我會認真考慮重組您的程序，但這絕對是一個好的開始。 您仍然可以使用類或函數對其進行格式化，但是讓函數之間進行無限次調用並不是一個好主意。

如果運行足夠長的時間，則此代碼的遞歸深度可能會遇到問題。 例如，您的choicesMenu函數將自行調用。 我知道您在做什么（以便循環播放），但是您實際上應該while這里使用while循環 。

原因如下：當choicesMenu尚未return或隱式返回並調用其他函數時，Python必須記住choicesMenu的狀態，因此當它從其他函數返回時，它將知道在哪里停止。 如果choicesMenu只是不斷調用自身，它將填滿該內存。