如何在PHP的數據庫mysqli表中選擇復選框

Question

**如何在數據庫mysqli中選擇復選框，我應該在復選框值中寫些什么，請幫助我也內爆將數組轉換為字符串的函數，但找不到要打印的復選框值的函數。 .....還要檢查圖片上的輸出... **

輸出圖片

        <?php
        while($fetch=mysqli_fetch_array($select))
        {
         ?>

        <tr>
        <td><?php echo $fetch["tableno"]?></td>
        <td><?php echo $fetch["customerid"]?></td>
        <td><?php echo $fetch["item"]?></td>
        <td><?php echo $fetch["money"]?></td>
        <td><a href="javascript:del_tableno(<?php echo $fetch["tableno"];?>)"><button>Delete</button></a></td>
        <td><a href="update.php?tableno=<?php echo $fetch["tableno"]; ?>"/><button>Update</button></td>

        <td><form method="POST">
            <input type="checkbox" name="chk[]" value="???">
            <input type="submit" name="sub1" value="Button for Checkbox">

            </td> </form>
        </tr>

        <?php

        }?>


    </table>

        <p style="font-size:30px">The Customer has TO Selected these Items from Menu List
    and therefore submitted to<br> Kitchener to Make the Food and
    then waiter will serve the Food to Customer.</p>
        </body>

    </html>
    <?php
     if(isset($_POST['sub1']))
      {
      $chk=implode(',', $_POST['chk']);
       echo "<br>Customer has  selected the following checkbox Item to be Prepared and Eat the Food:<br/>";

        echo "<br/>".$chk."<br><br/><br/><br/><br/>";

          }  

          ?>

Answer 1

嘗試這個：

在您的表單中，插入多個復選框的方法

<form method="POST" action="test2.php">
        <input type="checkbox" name="chk[]" value="InputText1">InputText1<br>
        <input type="checkbox" name="chk[]" value="InputText2">InputText2<br>
        <input type="submit" name="sub1">
</form>


if(isset($_POST['sub1'])) // check the submitted form and print the values
   {
     echo "You selected the following checkbox:<br/>";
     foreach ($_POST['chk'] as $value) {
      echo $value."<br>";
    }

Answer 2

一種方法是將復選框的值與所有數據連接起來，並在提交后，為每個循環檢查選中的復選框，並打印所有選中的行。 像下面

<input type="checkbox" name="chk[]" value="<?php echo "<td>".$fetch["tableno"]."</td><td>".$fetch["customerid"]."</td><td>".$fetch["item"]."</td><td>".$fetch["money"]."</td>"; ?>">

在發布后使​​用此：

if(isset($_POST['sub1'])) // check the submitted form and print the values
   {
     echo "Below Customers have placed orders:<br/>";
     echo "<table>";
     foreach ($_POST['chk'] as $value) {
      echo "<tr>".$value."</tr>";
    }
    echo "</table>";

}