使用列表設計可擴展的命令行界面

Question

這些是我的三個列表：

# made up data
products = ['apple','banana','orange'] 
prices = ['£0.11','£0.07','£0.05']
dates = ['02/04/2017','14/09/2018','06/08/2016']

重要的是要知道

• 這些列表中的數據將隨其大小而變化，但它們將保持相同的數據類型。
• 每個列表的第一個元素是鏈接的，同樣適用於第二個和第三個元素等...

所需的命令行界面：

Product | Price | Date of Purchase
--------|-------|------------------
 apple  | £0.11 |    02/04/2017
--------|-------|------------------
 banana | £0.07 |    14/09/2018
--------|-------|------------------
 orange | £0.05 |    06/08/2016

我想創建一個這樣的表。 如果每個列表中有更多元素但我不知道如何創建它，它顯然應該繼續。

我可以做

print(""" Product | Price | Date of Purchase   # etc...
          --------|-------|------------------
              %s  |   %s  |     %s 
""" % (products[0],prices[0],dates[0])) 

但我認為這將是對接口的硬編碼，這不是理想的，因為列表具有未確定的長度

有幫助嗎？

Answer 1

試試熊貓：

import pandas as pd
products = ['apple','banana','orange'] 
prices = ['£0.11','£0.07','£0.05']
dates = ['02/04/2017','14/09/2018','06/08/2016']

df = pd.DataFrame({"Product": products, "Price": prices, "Date of Purchase": dates})

print(df)

輸出：

  Product  Price Date of Purchase
0   apple  £0.11       02/04/2017
1  banana  £0.07       14/09/2018
2  orange  £0.05       06/08/2016

Answer 2

import beautifultable
from beautifultable import BeautifulTable
table = BeautifulTable()
# made up data
products = ['apple','banana','orange'] 
prices = ['£0.11','£0.07','£0.05']
dates = ['02/04/2017','14/09/2018','06/08/2016']

table.column_headers=['Product' ,'Price','Date of Purchase']
for i in zip(products,prices,dates):
    table.append_row(list(i))
print(table)

輸出是：

+---------+-------+------------------+
| Product | Price | Date of Purchase |
+---------+-------+------------------+
|  apple  | £0.11 |    02/04/2017    |
+---------+-------+------------------+
| banana  | £0.07 |    14/09/2018    |
+---------+-------+------------------+
| orange  | £0.05 |    06/08/2016    |
+---------+-------+------------------+

Answer 3

如果你想要一個不使用庫的版本，這里有一個相當簡單的函數，可以使用一些列表推導

def print_table(headers, *columns):
    # Ignore any columns of data that don't have a header
    columns = columns[:len(headers)]

    # Start with a space to set the header off from the left edge, then join the header strings with " | "
    print(" " + " | ".join(headers))
    # Draw the header separator with column dividers based on header length
    print("|".join(['-' * (len(header) + 2) for header in headers]))

    # Iterate over all lists passed in, and combine them together in a tuple by row
    for row in zip(*columns):
        # Center the contents within the space available in the column based on the header width
        print("|".join([
            col.center((len(headers[idx]) + 2), ' ')
            for idx, col in enumerate(row)
        ]))

這不會處理比列標題長度+ 2更長的單元格值。但是，通過截斷單元格內容可以很容易地實現（ 這里可以看到字符串截斷的示例）。