[英]How to convert JsValue to a Model Class with Scala in Play framework?
我試圖設置一個從天氣API獲得的JSON響應以適合我定義的模型類,以便輕松使用它,但是我做不到。
這是課程:
import play.api.libs.json._
import play.api.libs.functional.syntax._
case class Forecast(var main: String, var description: String, var temp: Int, var tempMin: Int, var tempMax: Int)
object Forecast {
implicit val forecastJsonFormat: Reads[Forecast] = (
(JsPath \ "weather" \\"main").read[String] and
(JsPath \ "weather" \\"description").read[String] and
(JsPath \ "main" \\"temp").read[Int] and
(JsPath \ "main" \\"temp_min").read[Int] and
(JsPath \ "main" \\"temp_max").read[Int]
) (Forecast.apply _)
}
這是控制器中的代碼:
def weather = Action.async {
futureResponse.map(response => {
val jsonString = response.json.toString()
val jsonObject = Json.parse(jsonString)
// TODO: Create t [Forecast] Object which represents the response.json data to send it to the view below
Ok(views.html.weather(t))
})}
我得到的response.json的示例:
{"coord":{"lon":37.62,"lat":55.75},"weather":[{"id":600,"main":"Snow","description":"light snow","icon":"13n"},{"id":701,"main":"Mist","description":"mist","icon":"50n"}],"base":"stations","main":{"temp":269.15,"pressure":1024,"humidity":92,"temp_min":268.15,"temp_max":270.15},"visibility":3100,"wind":{"speed":2,"deg":200},"clouds":{"all":90},"dt":1546266600,"sys":{"type":1,"id":9029,"message":0.0029,"country":"RU","sunrise":1546235954,"sunset":1546261585},"id":524901,"name":"Moscow","cod":200}
您必須將main
更改為Seq[String]
並將description
更改為Seq[String]
並將temp
, tempMin
, tempMax
為Double
我在這里使用了一種不同的方式來創建reads
,但是如果格式與預期的格式不同,則這種方式將引發異常。
case class Forecast(main: Seq[String], description: Seq[String], temp: Double, tempMin: Double, tempMax: Double)
object Forecast {
val reads = new Reads[Forecast] {
override def reads(json: JsValue): JsResult[Forecast] = {
val main = (json \ "weather" \\ "main").map(_.as[String]).toList
val description = (json \ "weather" \\ "description").map(_.as[String]).toList
val temp = (json \ "main" \ "temp").as[Double]
val tempMin = (json \ "main" \ "temp_min").as[Double]
val tempMax = (json \ "main" \ "temp_max").as[Double]
JsSuccess(Forecast(main, description, temp, tempMin, tempMax))
}
}
}
或者您可以使用相同的方式,但以不同的方式解析列表:
val forecastJsonFormat: Reads[Forecast] = (
(JsPath \ "weather").read[List[Map[String, JsValue]]].map(_.map(_("main").as[String])) and
(JsPath \ "weather").read[List[Map[String, JsValue]]].map(_.map(_("description").as[String])) and
(JsPath \ "main" \ "temp").read[Double] and
(JsPath \ "main" \ "temp_min").read[Double] and
(JsPath \ "main" \ "temp_max").read[Double]
) (Forecast.apply _)
我終於要做到了,這是怎么做的:
在模型中,我定義了我的案例類和一個伴侶對象,該對象解析從Web API到我的類參數的JSON響應
型號代碼:
import play.api.libs.json._
import play.api.libs.functional.syntax._
case class Forecast(main: String, description: String, temp: Double, tempMin: Double, tempMax: Double)
object Forecast {
implicit val forecastReads: Reads[Forecast] = (
(JsPath \ "weather" \\ "main").read[String] and
(JsPath \ "weather" \\ "description").read[String] and
(JsPath \ "main" \ "temp").read[Double] and
(JsPath \ "main" \ "temp_min").read[Double] and
(JsPath \ "main" \ "temp_max").read[Double]
) (Forecast.apply _)
}
在控制器代碼中,我添加了一個模式匹配,在這里!
控制器代碼:
def weather = Action.async {
futureResponse.map(response => {
val parseResult = Json.fromJson[Forecast](response.json)
parseResult match {
case JsSuccess(forecast, JsPath) => Ok(views.html.weather(forecast))
case JsError(error) => InternalServerError("Something went wrong!!") // Note that I'm not sure this result exists in Play...
}
})
}
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