[英]How can I create a dynamic matrix structure using only pointers?
我正在做一個只能使用指針的程序,也就是說,我必須在不使用數組的情況下加載帶有字母湯的文本文件。 此湯的每個字母周圍有8個指針,這些指針指向相鄰的字母。
我已經有一個代碼結構,但是我不能在這里做更多的事情。
有人可以幫忙嗎?
typedef struct letter ///estrutura para cada letra da sopa
{
char *lname;
struct letter *Norte;
struct letter *Sul;
struct letter *Este;
struct letter *Oeste;
struct letter *Nordeste;
struct letter *Sudeste;
struct letter *Sudoeste;
struct letter *Noroeste;
struct letter *pnext;
} LETTER;
typedef struct soup ///estrutura para a sopa de letras
{
int lin;
int col;
LETTER *pfirst;
} SOUP;
void read_soup_txt(SOUP *pcs, char *fn, int lin, int col) {
FILE *fp;
fp = fopen(fn, "r");
char c;
if (fp != NULL) {
pcs->lin = lin;
pcs->col = col;
LETTER *current = malloc(sizeof(LETTER)), *previous;
pcs->pfirst = current;
for (int i = 0; i < pcs->lin; i++) ///linhas
{
for (int j = 0; i < pcs->col; j++) ///colunas
{
fscanf(fp, "%c", &c); ///le o char
current->lname = malloc(sizeof(char)); ///aloca espaço para o char
strcpy(current->lname, &c); ///copia o char para a estrutura
previous = current;
if (i == 0 && j == 0) ///letra canto superior esquerdo
{
current->Norte = NULL;
current->Sul = NULL;
current->Este = NULL;
current->Oeste = NULL;
current->Noroeste = NULL;
current->Nordeste = NULL;
current->Sudeste = NULL;
current->Sudoeste = NULL;
}
if (i == 0 && j > 0 && j < pcs->col - 1) ///primeira linha
{
current->Norte = NULL;
current->Sul = NULL;
current->Este = NULL;
current->Oeste = NULL;
current->Noroeste = NULL;
current->Nordeste = NULL;
current->Sudeste = NULL;
current->Sudoeste = NULL;
}
if (i == 0 && j == pcs->col - 1) ///letra do canto superior direito
{
current->Norte = NULL;
current->Sul = NULL;
current->Este = NULL;
current->Oeste = NULL;
current->Noroeste = NULL;
current->Nordeste = NULL;
current->Sudeste = NULL;
current->Sudoeste = NULL;
}
if (i > 0 && i < pcs->lin && j == 0) ///letras na coluna da esquerda
{
current->Norte = NULL;
current->Sul = NULL;
current->Este = NULL;
current->Oeste = NULL;
current->Noroeste = NULL;
current->Nordeste = NULL;
current->Sudeste = NULL;
current->Sudoeste = NULL;
}
if (i == pcs->lin - 1 && j == 0) ///letra do canto inferior esquerdo
{
current->Norte = NULL;
current->Sul = NULL;
current->Este = NULL;
current->Oeste = NULL;
current->Noroeste = NULL;
current->Nordeste = NULL;
current->Sudeste = NULL;
current->Sudoeste = NULL;
}
if (i == pcs->lin - 1 && j > 0 && j < pcs->col - 1) ///ultima linha
{
current->Norte = NULL;
current->Sul = NULL;
current->Este = NULL;
current->Oeste = NULL;
current->Noroeste = NULL;
current->Nordeste = NULL;
current->Sudeste = NULL;
current->Sudoeste = NULL;
}
if (i == pcs->lin - 1 && j == pcs->col - 1) ///letra do canto inferior direito
{
current->Norte = NULL;
current->Sul = NULL;
current->Este = NULL;
current->Oeste = NULL;
current->Noroeste = NULL;
current->Nordeste = NULL;
current->Sudeste = NULL;
current->Sudoeste = NULL;
}
if (i > 0 && i < pcs->lin - 1 && j == pcs->col - 1) ///letras da coluna direita
{
current->Norte = NULL;
current->Sul = NULL;
current->Este = NULL;
current->Oeste = NULL;
current->Noroeste = NULL;
current->Nordeste = NULL;
current->Sudeste = NULL;
current->Sudoeste = NULL;
}
if (i > 0 && i < pcs->lin - 1 && j > 0 && j < pcs->col - 1) ///letras do meio do tabuleiro
{
current->Norte = NULL;
current->Sul = NULL;
current->Este = NULL;
current->Oeste = NULL;
current->Noroeste = NULL;
current->Nordeste = NULL;
current->Sudeste = NULL;
current->Sudoeste = NULL;
}
previous->pnext = current;
}
}
} else
printf("Erro ao abrir arquivo!");
fclose(fp);
}
也許嘗試讀取結構體中的所有字母,然后填充指針
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