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從非靜態的多維數組獲取頁面ID

[英]Getting page id from a multidimensional array which isn't static

我試圖從$ arr獲取ID密鑰的值,而不指定其來自哪個嵌套數組。 因此從$ arr中的所有嵌套數組返回ID。

$arr =array(
array(
        'title' => 'home',
        'ID' => '45'
    ),

array(
        'title' => 'articleholder',
        'ID' => '25'
    ),

array(
        'title' => 'article page',
        'ID' => '23'
    )

$arr = SiteTree::get()->filter('ParentID', $page['ID'])->toNestedArray();
$id = 'ID'
var_dump($arr[$id]); //returns ['45, 25, 23']

如果可以將以下內容定義為函數:

var_dump($arr[array_reverse_search_allnested($id)]

抱歉任何錯誤,這是一個小項目,我對php的介紹。

從過濾的站點樹返回的實際數組:

    array(0) {} array(0) {} array(0) {} array(0) {} array(0) {} array(0) {} array(0) {} array(0) {} array(0) {} array(1) {
    [
        0
    ]=> array(16) {
        [
            "ClassName"
        ]=> string(4) "Page" [
            "LastEdited"
        ]=> string(19) "2019-01-08 03:58:54" [
            "Created"
        ]=> string(19) "2019-01-08 03:58:43" [
            "CanViewType"
        ]=> string(7) "Inherit" [
            "CanEditType"
        ]=> string(7) "Inherit" [
            "Version"
        ]=> string(1) "3" [
            "URLSegment"
        ]=> string(7) "level-2" [
            "Title"
        ]=> string(7) "Level 2" [
            "ShowInMenus"
        ]=> string(1) "1" [
            "ShowInSearch"
        ]=> string(1) "1" [
            "Sort"
        ]=> string(1) "1" [
            "HasBrokenFile"
        ]=> string(1) "0" [
            "HasBrokenLink"
        ]=> string(1) "0" [
            "ParentID"
        ]=> string(2) "23" [
            "ID"
        ]=> int(24) [
            "RecordClassName"
        ]=> string(4) "Page"
    }
}

我想您正在尋找從多維數組中提取一列的array_column。

$id = array_column($arr, "ID");
var_dump($id);

返回值:

array(3) {
  [0]=>
  string(2) "45"
  [1]=>
  string(2) "25"
  [2]=>
  string(2) "23"
}

或者,您可以將第三個參數用作ID並獲取以下輸出:

$id = array_column($arr, "title","ID");
var_dump($id);

/*array(3) {
  [45]=>
  string(4) "home"
  [25]=>
  string(13) "articleholder"
  [23]=>
  string(12) "article page"
}*/

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