[英]How to iterate through a string and find the duplicated values
我的問題是,我似乎找不到正確的方法來遍歷subject2並挑選出重復的字符串。 下面是我的方法:
nosubjects = []
subjects2 = ["hi","hi","bi","ki","si","bi","li"]
for i in subjects2:
if subjects2.count(i)==2:
nosubjects.extend(i)
print(nosubjects)
但是當我打印出來時,它看起來像這樣:
['hi','hi']
['h', 'i', 'h', 'i','b', 'i']
['hi', 'i', 'h', 'i', 'b', 'i', 'b', 'i']
請幫忙謝謝!
使用collections.Counter
可以獲取每個元素的計數,並僅獲取計數超過1的元素:
from collections import Counter
subjects2 = ['hi', 'hi', 'bi', 'ki', 'si', 'bi', 'li']
nosubjects = [x for x, i in Counter(subjects2).items() if i > 1]
print(nosubjects)
# ['hi', 'bi']
您的代碼中的問題:
nosubjects
,這將導致它多次打印 使用sets
。 首先獲取列表中唯一的元素集,然后可以檢查原始列表中集合中每個元素的計數是否超過1。
nosubjects = []
subjects2 = ['hi','hi','bi','ki','si','bi','li']
for i in set(subjects2):
if subjects2.count(i)>=2:
nosubjects.append(i)
print(nosubjects)
使用列表理解:
subjects2 = ['hi','hi','bi','ki','si','bi','li']
nosubjects = [i for i in set(subjects2) if subjects2.count(i) >=2]
print(nosubjects)
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