從異步函數返回列表

Question

我從下面有以下代碼。 我知道在某處可能是錯誤的，但是在運行后可以返回列表電報列表必須怎么辦？ 只想可以全局訪問列表項？

telegramlist = []
telegramchannellist = ['TelethonChat-anti-kyle']


async def telegram_method():
    api_id = '*'
    api_hash = '*'

    client = TelegramClient('trendingsesion', api_id, api_hash)
    client.start()

    telegramdict = {}
    for ch in telegramchannellist:
        channel_username = ch
        channel_entity = client.get_entity(channel_username)
        posts = client(GetHistoryRequest(
            peer=channel_entity,
            limit=1,
            offset_date=None,
            offset_id=0,
            max_id=0,
            min_id=0,
            add_offset=0,
            hash=0))
        telegramdict[ch] = posts.messages # here if i write .messages shows a weird error, he want to be only posts
    telegramlist = list(telegramdict.values())
    return telegramlist

shuffle(telegramchannellist)
if __name__ == '__main__':
    loop = asyncio.get_event_loop()
    telegramlistt = loop.run_until_complete(asyncio.gather(telegram_method()))
    loop.close()

Answer 1

您在main協程中缺少await 。 已更正，它看起來像這樣：

async def main():
    telegramlist = await telegram_method()
    return telegramlist