[英]Upload directory with sub-directories in java and azure blob storage sdk
我使用此代碼將文件上傳到azure blob存儲,但是當我嘗試使用子目錄加載目錄時,出現錯誤“遇到FileNotFoundException:C:\\ upload \\ bin” :(訪問被拒絕),是加載文件和源目錄中的目錄?
try {
CloudStorageAccount account = CloudStorageAccount.parse(storageConnectionString);
CloudBlobClient serviceClient = account.createCloudBlobClient();
// Container name must be lower case.
CloudBlobContainer container = serviceClient.getContainerReference(containerName);
container.createIfNotExists();
File source = new File(path);
if (source.list().length > 0) {
for (File file : source.listFiles()) {
CloudBlockBlob blob = container.getBlockBlobReference(file.getName());
if (blob.exists() == false) {
File sourceFile = new File(source + "\\" + file.getName());
blob.upload(new FileInputStream(sourceFile), sourceFile.length());
System.out.println("File " + source + "\\" + file.getName() + " Load to blob storage");
} else System.out.println("File " + source + "\\" + file.getName() + " Already exist in storage");
}
} else System.out.println("In folder " + path + " are no files ");
} catch (FileNotFoundException fileNotFoundException) {
System.out.print("FileNotFoundException encountered: ");
System.out.println(fileNotFoundException.getMessage());
System.exit(-1);
} catch (StorageException storageException) {
System.out.print("StorageException encountered: ");
System.out.println(storageException.getMessage());
System.exit(-1);
} catch (Exception e) {
System.out.print("Exception encountered: ");
System.out.println(e.getMessage());
System.exit(-1);
}
就像@ ZhaoxingLu-Microsoft所說的那樣, source.listFiles()
生成的file
對象足以通過file.getAbsolutePath()
獲取絕對文件路徑,因此您可以編寫以下代碼。
if (blob.exists() == false) {
blob.uploadFromFile(file.getAbsolutePath());
} else System.out.println("File " + file.getAbsolutePath() + " Already exist in storage");
我在我的環境中測試您的代碼,它也可以工作。 但是,根據我的經驗, FileNotFoundException encountered: C:\\upload\\bin" :(Access is denied)
問題FileNotFoundException encountered: C:\\upload\\bin" :(Access is denied)
是由於缺少對C:
或C:\\upload\\bin
下文件的訪問權限所致。因此,您需要運行如下圖所示,以管理員身份在當前Windows環境中執行代碼。
圖1.如果使用IntelliJ,請以管理員身份運行代碼
圖2.如果使用Eclipse以管理員身份運行代碼
圖3.通過命令提示符以管理員身份運行代碼
更新 :在Azure Blob存儲上,文件和目錄結構取決於Blob名稱。 因此,如果您要查看如下圖所示的文件結構,可以使用代碼String blobName = file.getAbsolutePath().replace(path, "");
獲取Blob名稱。
圖5.通過Azure Storage Explorer在Azure Blob存儲上的上述操作
這是我完整的代碼。
private static final String path = "D:\\upload\\";
private static final String storageConnectionString = "<your storage connection string>";
private static final String containerName = "<your container for uploading>";
private static CloudBlobClient serviceClient;
public static void upload(File file) throws InvalidKeyException, URISyntaxException, StorageException, IOException {
// Container name must be lower case.
CloudBlobContainer container = serviceClient.getContainerReference(containerName);
container.createIfNotExists();
String blobName = file.getAbsolutePath().replace(path, "");
CloudBlockBlob blob = container.getBlockBlobReference(blobName);
if (blob.exists() == false) {
blob.uploadFromFile(file.getAbsolutePath());
} else {
System.out.println("File " + file.getAbsolutePath() + " Already exist in storage");
}
}
public static void main(String[] args)
throws URISyntaxException, StorageException, InvalidKeyException, IOException {
CloudStorageAccount account = CloudStorageAccount.parse(storageConnectionString);
serviceClient = account.createCloudBlobClient();
File source = new File(path);
for (File fileOrDir : source.listFiles()) {
boolean isFile = fileOrDir.isFile();
if(isFile) {
upload(fileOrDir);
} else {
for(File file: fileOrDir.listFiles()) {
upload(file);
}
}
}
}
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