[英]How can I fetch user ID after overriding it with different primary key in Eloquent ORM?
用戶模型返回id=null
,而調試時我發現此問題的原因是在我的User
模型中,我User
自定義$primary_key
覆蓋了$primary_key
class User extends Authenticatable
{
use Notifiable;
// Set the primary key to the generated version instead of the regular ID
protected $primaryKey = 'user_code';
// Set the key type
protected $keyType = 'string';
// Diable the auto-increment option
public $incrementing = false;
/**
* The attributes that are mass assignable.
*
* @var array
*/
protected $fillable = [
'user_code',
'fname',
'mname',
'lname',
'email',
'dob',
'age',
'gender',
'insurance_number',
'ssn',
'avatar',
'is_active',
'userable_id',
'userable_type',
];
}
我有以下代碼生成使用id
的新user_code
$user = new User;
$user = $user->create([
'fname' => $request->fname,
'lname' => $request->lname,
'email' => $request->email,
]);
// Save the user in the DB
// Generate a usercode for the newely created user
$userCode = "ur" . date('y') . date('m') . $user->id;
用戶遷移:
Schema::create('users', function (Blueprint $table) {
$table->increments('id');
$table->string('user_code')->unique()->nullable();
$table->string('fname')->default('tbd');
$table->string('mname')->default('tbd');
$table->string('lname')->default('tbd');
$table->string('email')->unique()->nullable();
$table->date('dob')->default('1000-01-01');
$table->integer('age')->default(0);
$table->string('gender')->default('tbd');
$table->integer('insurance_number')->default(0);
$table->integer('ssn')->default(0);
$table->string('avatar')->default('tbd');
$table->boolean('is_active')->default(false);
$table->string('userable_code')->default('tbd');
$table->string('userable_type')->default('tbd');
$table->timestamp('email_verified_at')->nullable();
$table->rememberToken();
$table->timestamps();
});
$user->id
返回null,為什么會發生這種現象?
您已將$user
設置為新的模型實例:
$user = new User;
但是,然后您嘗試從該實例創建一個新用戶,這將不起作用:
$user = $user->create([ ...
由於這行不通,因此您實際上並沒有將任何內容保存到數據庫,也不會獲得ID。
問題的第二部分是(如@TimLewis在注釋中指出的那樣),您正在嘗試創建和保存帶有空白主鍵( user_code
)的模型。 那是行不通的,因此您需要先弄清楚ID是什么, 然后再嘗試保存它。
// Remove this line:
// $user = new User;
// Find the current highest ID:
$last = User::max('id');
// Your new user will have this ID
$newID = $last->id + 1;
// And just use the normal way to create and save a model:
$user = User::create([
'userCode' => "ur" . date('y') . date('m') . $newID,
'fname' => $request->fname,
'lname' => $request->lname,
'email' => $request->email,
]);
我可能不知道您要在這里實現什么,但是我只是假設這是一個非常特殊的用例。
嘗試這個:
// Notice how we are using the User as a class, not instantiating it.
$user = User::create([
'fname' => $request->fname,
'lname' => $request->lname,
'email' => $request->email,
]);
// Save the user in the DB
// Generate a usercode for the newely created user
$userCode = "ur" . date('y') . date('m') . $user->id;
假設您的數據庫表中的id
列仍為INCREMENTS
和PRIMARY KEY
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