如何從Google Maps API-地方獲取完整地址？

Question

我正在嘗試從Google地圖自動填充中獲取完整的地址，但是它不起作用。 看到我的代碼和我的控制台

var placeSearch, autocomplete;
var componentForm = [
    'delivery-street',
    'delivery-suburb',
    'delivery-postcode',
    'delivery-city',
    'delivery-country'
];

window.initAutocomplete = function() {
    // Create the autocomplete object, restricting the search to geographical
    // location types.
    autocomplete = new google.maps.places.Autocomplete(
        /** @type {!HTMLInputElement} */(document.getElementById('autocomplete')),
        {types: ['geocode']});

    // When the user selects an address from the dropdown, populate the address
    // fields in the form.
    autocomplete.addListener('place_changed', fillInAddress);
}

function fillInAddress() {
    // Get the place details from the autocomplete object.
    var place = autocomplete.getPlace();

    console.log(place);
    for (var component in componentForm) {
        document.getElementById(componentForm[component]).value = '';
        document.getElementById(componentForm[component]).disabled = false;
    }

    // Get each component of the address from the place details
    // and fill the corresponding field on the form.
    document.getElementById('delivery-street').value = findAttr(place, ['street_number']) + ' ' + findAttr(place, ['route']);
    document.getElementById('delivery-suburb').value = findAttr(place, ['sublocality_level_1', 'locality']);
    document.getElementById('delivery-postcode').value = findAttr(place, ['postal_code']);
    document.getElementById('delivery-city').value = findAttr(place, ['administrative_area_level_1', 'route']);
    document.getElementById('delivery-country').value = findAttr(place, ['country']);
}

function findAttr(place, findType) {
    var response = [];
    for (var j = 0; j < findType.length; j++) {

        for (var i = 0; i < place.address_components.length; i++) {
            var addressType = place.address_components[i].types[0];
            if(addressType === findType[j]){
                response.push(place.address_components[i].long_name);
            }
        }

    }
    return response.join(', ')
}

// Bias the autocomplete object to the user's geographical location,
// as supplied by the browser's 'navigator.geolocation' object.
window.geolocate = function () {
    if (navigator.geolocation) {
        navigator.geolocation.getCurrentPosition(function(position) {
            var geolocation = {
                lat: position.coords.latitude,
                lng: position.coords.longitude
            };
            var circle = new google.maps.Circle({
                center: geolocation,
                radius: position.coords.accuracy
            });
            autocomplete.setBounds(circle.getBounds());
        });
    }
}

因此，我輸入了“ 2/89 Union St，New Brighton，Christchurch，New Zealand”，這就是控制台中的結果

address_components: Array(7)
0: {long_name: "89", short_name: "89", types: Array(1)}
1: {long_name: "Union Street", short_name: "Union St", types: Array(1)}
2: {long_name: "New Brighton", short_name: "New Brighton", types: Array(3)}
3: {long_name: "Christchurch", short_name: "Christchurch", types: Array(2)}
4: {long_name: "Canterbury", short_name: "Canterbury", types: Array(2)}
5: {long_name: "New Zealand", short_name: "NZ", types: Array(2)}
6: {long_name: "8061", short_name: "8061", types: Array(1)}

在文檔中說

Autocomplete構造函數采用兩個參數：

• geocode指示Places服務僅返回地理編碼結果，而不返回業務結果。
• address指示Places服務僅返回具有精確地址的地理編碼結果。

我嘗試使用“地址”，但沒有任何變化

• 關於如何獲取公寓/單元/公寓號的任何想法？

Answer 1

我遇到了同樣的問題，最終只是創建了一個函數來構建所需的地址。 這對美國非常有用。 我不確定英國...

getAddressFromComponents(geo: any) {
    const streetNumber = geo.find( g => g.types.find( t => t === 'street_number') ).long_name;
    const streetName = geo.find( g => g.types.find( t => t === 'route' )).long_name;
    const cityName = geo.find( g => g.types.find( t => t === 'locality') && g.types.find( t => t === 'political' )).long_name;
    const stateName = geo.find( g => g.types.find( t => t === 'administrative_area_level_1') && g.types.find( t => t === 'political' ))
      .long_name;
    const countryName = geo.find( g => g.types.find( t => t === 'country') && g.types.find( t => t === 'political' )).long_name;
    const zip = geo.find( g => g.types.find( t => t === 'postal_code' )).long_name;

    return {
      address: `${streetNumber} ${streetName}`,
      city: cityName,
      state: stateName,
      country: countryName,
      postalCode: zip
    };
  }

用法

const address = this.getAddressFromComponents( _geoResponse[ 0 ].address_components );

物有所值，我們將改用Algolia Places，因為它更易於使用：

https://community.algolia.com/places/