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簡化三重嵌套循環,以避免在Android Retrofit2中回調地獄(通過RxJava2嗎?)

[英]Simplifying triple nested loop to avoid callback hell in android retrofit2 (via RxJava2?)

上下文

使用android retrofit2,需要訪問深層嵌套的name字符串以獲取並顯示其Details (其中Detail的對象引用了用於獲取DetailGroupUser對象)。

JSON由一個Group列表組成,每個Group包含一個User列表,每個User包含一個name String列表,這些name在以下模型中捕獲:

public class Group {
    @SerializedName("id")
    public String id;
    @SerializedName("users")
    public List<User> users;
}
public class User {
    @SerializedName("id")
    public String id;
    @SerializedName("detailNames")
    public List<String> detailNames;
}
public class Detail {
    // allow access to objects used to get detail
    public Group group;
    public User user;
    @SerializedName("name")
    public String name;
    @SerializedName("description")
    public String description;
}

使用UserApi填充模型:

public interface UserApi {
    @GET("groups")
    Call<List<Group>> getGroups();

    @GET("groups/{group_id}/users/{user_id}/details/{detail_name}")
    Call<Detail> getDetail(
            @Path("group_id") String groupId,
            @Path("user_id") String userId,
            @Path("detail_name") String detailName
    );
}

目標

目的是使用給定的UserApi發出和解析請求以顯示以下格式的Dialog

Group1 (expandable heading)
    User1 (expandable heading)
        Detail1 (checkbox)
        Detail2 (checkbox)
        ...
Group2 (expandable heading)
    User2 (expandable heading)
        Detail1 (checkbox)
        ...
    ...
...

問題

問題是當前解決方案請求Group並使用三重嵌套的for循環訪問和獲取每個name Detail

private void fetchDetails(List<Group> groupList) {
    ArrayList<Group> groups = (ArrayList<Group>) groupList;
    if (groups != null && groups.size() > 0) {
        for (Group group : groups) {
            for (User user: group.users) {
                for (String detailName : user.detailNames) {
                    fetchDetail(group, user, detailName);
                }
            }
        }
    }
}

由於三重循環為每個name發出請求,並且在getGroups onResponse回調中完成,因此問題變得更加嚴重,這似乎onResponse /無法維護:

protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    mUserApi = UserApiClient.getApi();
    fetchGroups();
}
private void fetchGroups() {
    Callback<List<Group>> groupsCall = new Callback<List<Group>>() {
        @Override
        public void onResponse(Call<List<Group>> call, Response<List<Group>> response) {
            int statusCode = response.code();
            switch (statusCode) {
                case HttpURLConnection.HTTP_OK:
                    List<Group> groups = response.body();
                    fetchDetails(groups);
                    break;
            }
        }
        @Override
        public void onFailure(Call<List<Group>> call, Throwable t) {}
    };
    mUserApi.getGroups().enqueue(groupsCall);
}
private void fetchDetail(final Group group, final User user, String detailName) {
    Callback<Detail> detailCallback= new Callback<Detail>() {
        @Override
        public void onResponse(Call<Detail> call, Response<Detail> response) {
            int statusCode = response.code();
            switch (statusCode) {
                case HttpURLConnection.HTTP_OK:
                    MainActivity.this.runOnUiThread(new Runnable() {
                        @Override
                        public void run() {
                            // display details in ListView
                        }
                    });
                    break;
            }
        }
        @Override
        public void onFailure(Call<Detail> call, Throwable t) {}
    };
    mUserApi.getDetail(group.id, user.id, detailName).enqueue(detailCallback);
}

建議使用RxJava2解決方案來避免像上述實現那樣嵌套回調,但由於在管理3層嵌套訪問names方面存在困惑,因此未完成:

Observable<List<Group>> groupCall =  mUserApi.getGroups();
groupCall.flatMapIterable(x -> x)
   .flatMap(group -> {
       Observable.fromIterable(group.users)
           .flatMap(user -> {
               Observable.fromIterable(user.detailNames)
                   .map(detailName -> {
                        mUserApi.getDetail(group.id, user.id, detailName)
                            .flatMap(detail -> {
                                detail.group = group;
                                detail.user = user;
                                return Observable.just(detail)
                            })
                            .subscribeOn(Schedulers.io())
                            .observeOn(AndroidSchedulers.mainThread())
                            .subscribe(new Observer<List<Group>>() {
                                @Override
                                public void onSubscribe(Disposable d) {}
                                @Override
                                public void onNext(List<Detail> value) {
                                    mDetails = (ArrayList<Detail>) value;
                                }
                                @Override
                                public void onError(Throwable e) {}
                                @Override
                                public void onComplete() {}
                            });
                   });
           }
   })

存在一些問題(例如, 帶有條件的RxJava多循環 )可以處理RxJava中的嵌套,但仍不確定如何將其應用於深度嵌套的name s。

是否可以使用RxJava2避免回調地獄並簡化三重for循環,還有其他方法,還是該解決方案應訴諸AsyncTask / AsyncTaskLoader同步請求?

正如我在評論中提到的那樣,我認為您已經擁有的幾乎是最簡單的表格。 但是似乎您有興趣在沒有循環的情況下執行此操作,因此這里有一些建議(但不一定更好):

方法1:容器類

如果您願意創建可以在單個對象中容納組,用戶,詳細信息名稱的中間容器類,則可以執行以下操作:

首先,創建以下容器類:

public class UserWithGroup {
    final Group group;
    final User user;

    public UserWithGroup(Group group, User user) {
        this.group = group;
        this.user = user;
    }
}

public class DetailWithUser {
    final Group group;
    final User user;
    final String detailName;

    public DetailWithUser(Group group, User user, String detailName) {
        this.group = group;
        this.user = user;
        this.detailName = detailName;
    }
}

然后,使用Java 8 Stream的代碼可以是:

private void fetchDetails(List<Group> groupList) {
    groupList.stream()
            .flatMap(g -> g.users.stream().map(u -> new UserWithGroup(g, u)))
            .flatMap(ug -> ug.user.detailNames.stream().map(n -> new DetailWithUser(ug.group, ug.user, n)))
            .forEach(d -> fetchDetail(d.group, d.user, d.detailName));
}

或使用RxJava:

private void fetchDetails2(List<Group> groupList) {
    Observable.fromIterable(groupList)
            .flatMap(g -> Observable.fromIterable(g.users).map(u -> new UserWithGroup(g, u)))
            .flatMap(ug -> Observable.fromIterable(ug.user.detailNames).map(n -> new DetailWithUser(ug.group, ug.user, n)))
            .flatMap(d -> mUserApi.getDetail(d.group.id, d.user.id, d.detailName)
                    .map(detail -> {
                        detail.group = d.group;
                        detail.user = d.user;
                        return detail
                    }))
            .subscribeOn(Schedulers.io())
            .observeOn(AndroidSchedulers.mainThread())
            .subscribe(detail -> {
                ...
            });
}

方法2:

Android.util.Pair一個可以容納任何兩個對象的容器類。 如果使用此方法而不是創建中間容器,並且可以使用,則可以進一步簡化代碼。

Java 8流和配對:

private void fetchDetails3(List<Group> groupList) {
    groupList.stream()
            .flatMap(g -> g.users.stream().map(u -> Pair.create(g, u)))
            .flatMap(p -> p.second.detailNames.stream().map(n -> Pair.create(p, n)))
            .forEach(p -> fetchDetail(p.first.first, p.first.second, p.second));
}

RxJava和配對:

private void fetchDetails4(List<Group> groupList) {
    Observable.fromIterable(groupList)
            .flatMap(g -> Observable.fromIterable(g.users).map(u -> Pair.create(g, u)))
            .flatMap(p -> Observable.fromIterable(p.second.detailNames).map(n -> Pair.create(p, n)))
            .flatMap(p -> fetchDetail2(p.first.first, p.first.second, p.second)
                    .map(detail -> {
                        detail.group = d.group;
                        detail.user = d.user;
                        return detail
                    }))
            .subscribeOn(Schedulers.io())
            .observeOn(AndroidSchedulers.mainThread())
            .subscribe(detail -> {
                ...
            });
}

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