使用 Python 3 問題將文件上傳到 Google Cloud

Question

我有一個 Android 應用程序，它將通過 HTTP 請求發送視頻文件。 但是，當我嘗試發送文件時，Google Cloud 會出錯。 我正在使用 Python 3。

在倒數第二行blob.upload_from_filename(filename) 有問題，我想知道如何解決這個問題。

這是代碼：

import os
from google.cloud import storage
from flask import Flask, flash, request, redirect, url_for
from werkzeug.utils import secure_filename
bucket_name = 'Censored.appspot.com'
ALLOWED_EXTENSIONS = set(['txt', 'pdf', 'png', 'jpg', 'jpeg', 'gif', 'mp4'])

app = Flask(__name__)
app.config['UPLOAD_FOLDER'] = UPLOAD_FOLDER
app.config['SECRET_KEY'] = "TESTSTRING"

def allowed_file(filename):
    return '.' in filename and \
           filename.rsplit('.', 1)[1].lower() in ALLOWED_EXTENSIONS

@app.route('/', methods=['GET', 'POST'])
def upload_file():
    if request.method == 'POST':
        if 'file' not in request.files:
            flash('No file part')
            return redirect(request.url)
        file = request.files['file']
        if file.filename == '':
            flash('No selected file')
            return redirect(request.url)
        if file and allowed_file(file.filename):
            filename = secure_filename(file.filename)
            filepath = '/{}/{}'.format(bucket_name, filename)
            storage_client = storage.Client()
            bucket = storage_client.get_bucket(bucket_name)
            blob = storage.Blob(filename, bucket)
            blob.upload_from_filename(filename)
    return "Hello World!"

這是上傳時出現的錯誤：

  Traceback (most recent call last):


File "", line 1
        Traceback (most recent call last): 
File "/env/lib/python3.6/site-packages/flask/app.py", 
line 2292, in wsgi_app response = self.full_dispatch_request() 
File "/env/lib/python3.6/site-packages/flask/app.py", 
line 1815, in full_dispatch_request rv = self.handle_user_exception(e) 
File "/env/lib/python3.6/site-packages/flask/app.py", 
line 1718, in handle_user_exception reraise(exc_type, exc_value, tb) 
File "/env/lib/python3.6/site-packages/flask/_compat.py", 
line 35, in reraise raise value File "/env/lib/python3.6/site-packages/flask/app.py", 
line 1813, in full_dispatch_request rv = self.dispatch_request() 
File "/env/lib/python3.6/site-packages/flask/app.py", 
line 1799, in dispatch_request return self.view_functions[rule.endpoint](**req.view_args) 
File "/home/vmagent/app/__init__.py", 
line 32, in upload_file blob.upload_from_filename(filename) 
File "/env/lib/python3.6/site-packages/google/cloud/storage/blob.py", 
line 1021, in upload_from_filename with open(filename, 'rb') as file_obj: 
FileNotFoundError: [Errno 2] No such file or directory: '377bdc67c74336b6_101.mp4'
                             ^
    SyntaxError: invalid syntax

作為旁注； 在我使用的本地 Flask 服務器中：

    file.save(os.path.join(app.config['UPLOAD_FOLDER'], filename))

這當然在谷歌雲中不起作用，因為它使用存儲桶。

我在這里變得絕望了。 我想，我缺少一些關於谷歌雲的常識。

Answer 1

您錯過了實際保存文件的步驟：

filename = secure_filename(file.filename)
filepath = os.path.join(app.config['UPLOAD_FOLDER'], filename)
file.save(filepath)

對於 Google App Engine， UPLOAD_FOLDER必須是/tmp 。

保存文件后，您可以將其上傳到 Google Cloud Storage：

name = '/{}/{}'.format(bucket_name, filename)
storage_client = storage.Client()
bucket = storage_client.get_bucket(bucket_name)
blob = storage.Blob(name, bucket)
blob.upload_from_filename(filepath)

Answer 2

我認為這一行：

blob = storage.Blob(name, bucket)

真的應該

blob = storage.Blob(filename, bucket)

至少這就是它對我的工作方式。 否則，它最終會出現在嵌套在與存儲桶同名的存儲桶中的文件夾中。