如何在列表中的某個點之后從字符串中刪除字符？

Question

我在列表中有一個字符串列表，我想刪除第十個字符之后的每個字符串中的所有內容。

EX：

['0.04112243,0.04112243,right,4.11%', '0.12733313,0.05733313,right,12.73%', '0.09203131,0.02203131,right,9.2%']

我只需要列表中的前十個整數，其他所有內容都應從中刪除。

產量

['0.04112243', '0.12733313', '0.09203131']

Answer 1

您可以使用列表理解：

original = ['0.04112243,0.04112243,right,4.11%', '0.12733313,0.05733313,right,12.73%', '0.09203131,0.02203131,right,9.2%']

new = [s[:10] for s in original]

輸出：

['0.04112243', '0.12733313', '0.09203131']

如果您想在第一個逗號之前保留所有內容，也可以更加靈活一些：

new = [s.partition(',')[0] for s in original]

Answer 2

您可以訪問類似於數組的字符串字符。

碼：

example = ['0.04112243,0.04112243,right,4.11%', '0.12733313,0.05733313,right,12.73%', '0.09203131,0.02203131,right,9.2%']
for s in example:
    print(s[:10])

輸出：

0.04112243
0.12733313
0.09203131

Answer 3

列表理解和字符串切片：

dirty = ['0.04112243,0.04112243,right,4.11%', '0.12733313,0.05733313,right,12.73%', '0.09203131,0.02203131,right,9.2%']

clean = [num[:10] for num in dirty]

Answer 4

Split（）創建由指定字符分隔的字符串列表。 考慮到這一點，我將在逗號（，）char上拆分每個字符串，然后將第一個元素附加到列表中。

lst = ['0.04112243,0.04112243,right,4.11%', '0.12733313,0.05733313,right,12.73%', '0.09203131,0.02203131,right,9.2%']
result = []
for i in lst:
    result.append(i.split(",")[0])
#Test output
print(result)

這應該以所需的格式返回所需的值！ 希望這可以幫助。