[英]laravel : Return null token But used has added
我使用郵遞員在我的 Laravel 項目中添加用戶我得到空令牌但用戶添加了為什么?
{“令牌”:空}
我該如何解決這個錯誤? 我使用 laravel 5.6,這是我的用戶模型:
<?php
namespace App;
use Tymon\JWTAuth\Contracts\JWTSubject;
use Illuminate\Notifications\Notifiable;
use Illuminate\Foundation\Auth\User as Authenticatable;
class User extends Authenticatable
{
use Notifiable;
/**
* The attributes that are mass assignable.
*
* @var array
*/
protected $fillable = [
'name', 'email', 'password','username','lastname','tel','tel',
];
/**
* The attributes that should be hidden for arrays.
*
* @var array
*/
protected $hidden = [
'password', 'remember_token',
];
public function getJWTIdentifier()
{
return $this->getKey();
}
/**
* Return a key value array, containing any custom claims to be added to the JWT.
*
* @return array
*/
public function getJWTCustomClaims()
{
return [];
}
}
這是我的注冊控制器
<?php
namespace App\Http\Controllers;
use App\Http\Controllers\Controller;
use Illuminate\Http\Request;
use App\User;
use JWTFactory;
use JWTAuth;
use Validator;
use Response;
class APIRegisterController extends Controller
{
//
public function register( Request $request){
$validator = Validator::make($request -> all(),[
'email' => 'required|string|email|max:255|unique:users',
'username' =>'required',
'tel' => 'required',
'name' => 'required',
'lastname' => 'required',
'adress' => 'required',
'password'=> 'required'
]);
if ($validator -> fails()) {
# code...
return response()->json($validator->errors());
}
User::create([
'name' => $request->get('name'),
'email' => $request->get('email'),
'tel' => $request->get('tel'),
'username' => $request->get('username'),
'lastname' => $request->get('lastname'),
'adress' => $request->get('adress'),
'password'=> bcrypt($request->get('password'))
]);
$user = User::first();
$token = JWTAuth::fromUser($user);
return Response::json( compact('token'));
}
}
and this is my controller
<?php
namespace App\Http\Controllers;
use App\Http\Controllers\Controller;
use Illuminate\Http\Request;
use App\User;
use Illuminate\Support\Facades\Response;
use Tymon\JWTAuth\Facades\JWTAuth;
use Tymon\JWTAuth\Facades\JWTFactory;
use Validator;
class APIRegisterController extends Controller
{
//
public function register( Request $request){
$validator = Validator::make($request -> all(),[
'email' => 'required|string|email|max:255|unique:users',
'username' =>'required',
'tel' => 'required',
'name' => 'required',
'lastname' => 'required',
'adress' => 'required',
'password'=> 'required'
]);
if ($validator -> fails()) {
# code...
return response()->json($validator->errors());
}
User::create([
'name' => $request->get('name'),
'email' => $request->get('email'),
'tel' => $request->get('tel'),
'username' => $request->get('username'),
'lastname' => $request->get('lastname'),
'adress' => $request->get('adress'),
'password'=> bcrypt($request->get('password'))
]);
$user = User::first();
$token = JWTAuth::fromUser($user);
return Response::json( compact('token'));
}
}
我總是收到一個錯誤,這是我的問題,我修復了它
我該如何解決這個錯誤? 我使用 Laravel 5.6
我之前已經遇到過類似的問題,但我意識到我的$user->password
保存了加密的密碼,而不是login()
所需的痛苦文本。 更改您的代碼以調用
$token = JWTAuth::fromUser($user);
$user
持有來自$request
的純文本密碼
我解決了在創建用戶后在注冊功能上添加 if 條件的問題
if ($this->loginAfterSignUp) {
$token = $this->login($request);
}
return $this->respondWithToken($token);
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.