[英]unrecognized expression using template literals
執行此代碼:
let pathb = $('.cslideract').attr('data-pathb');
console.log(pathb);
我得到以下結果: anima/01/inc
。
現在,我嘗試在此功能中使用它:
if($(`.partslider[data-pathb=${pathb}]`).length > 0){console.log('323');}
我收到此錯誤:
unrecognized expression: .partslider[data-pathb=anima/01/inc/]
我用let pathb = 'anything'
嘗試了同樣let pathb = 'anything'
,它可以工作,但是我的變量是anima/01/inc
使用引號""
將文字括起來
let pathb = $('.cslideract').attr('data-pathb'); console.log(pathb); if($(`.partslider[data-pathb="${pathb}"]`).length > 0){console.log('323');}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script> <div class="cslideract" data-pathb="anima/01/inc"></div> <div class="partslider" data-pathb="anima/01/inc"></div>
您可以在CSS選擇器( $ .escapeSelector() )中轉義具有特殊含義的字符:
let pathb = 'anima/01/inc'; console.log(`.partslider[data-pathb=${$.escapeSelector(pathb)}]`); if($(`.partslider[data-pathb=${$.escapeSelector(pathb)}]`).length > 0){ console.log('323'); }
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
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