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[英]How can i get value from url in php codeigniter and want to display result according to that value
[英]Get result according to if condition in codeigniter
我正在使用以下代碼,如果狀態為“0”,則應顯示“已批准”,如果狀態為“1”,則應顯示不批准,我該怎么做,我嘗試使用以下代碼但對我不起作用
$this->db->select('*');
$this->db->from('surgery');
$this->db->where('doctor_id',$add_data['doctor_id']);
$query = $this->db->get();
if ( $queryc->num_rows() > 0 )
{
$rows = $query->result_array();
$newEntry=array();
foreach ($rows as $rown)
{
$newEntry = $rown;
if($rown['status']=="0")
{
$newEntry["status"] = "dissapproved";
}
else
{
$newEntry["status"] = "approved";
}
}
}
上面的代碼顯示一個結果/記錄,就像下面這樣
Array
(
[id] => 5
[status] => dissapproved
)
foreach ($rows as $rown)
{
if($rown['status']=="0")
{
$rown['status'] = "dissapproved";
}
else
{
$rown['status'] = "approved";
}
$newEntry =$rown;
}
您正在循環內替換數組$newEntry
。 這就是為什么你只會得到一個結果。 試試下面的代碼。
if ($query->num_rows() > 0) {
$rows = $query->result_array();
$newEntry = array();
foreach ($rows as $rown) {
if ($rown['status'] == "0") {
$rown["status"] = "dissapproved";
} else {
$rown["status"] = "approved";
}
$newEntry[] = $rown;
}
}
只需將$rown['status']
替換為新字符串approved
/ dissapproved
approved
然后將其添加到您的數組$newEntry
嘗試這個,
$i=0;
foreach ($rows as $col) {
//below code if you use $query->result();
if ($col->status == 0) {
$col->status = "dissapproved";
} else {
$col->status = "approved";
}
//below code if you use $query->result_array();
if ($col['status'] == 0) {
$rows[$i]['status'] = "dissapproved";
} else {
$rows[$i]['status'] = "approved";
}
$i++;
}
echo'<pre>';print_r($rows);die;
請先閱讀評論部分
在上面的模型查詢中,將 $queryc 更改為 $query 之類的
if ( $queryc->num_rows() > 0 ) Instead if ( $query->num_rows() > 0 )
將您的循環更改為此,希望它對您有用。
foreach ($rows as $rown)
{
$newEntry = $rown;
if($rown['status']=="0")
{
$newEntry["status"][] = "dissapproved";
}
else
{
$newEntry["status"][] = "approved";
}
}
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