![](/img/trans.png)
[英]Oracle SQL Update parent record depending on child records in the same table
[英]Oracle SQL - Listing records from Parent and Child Table in a certain order
我有兩個表T1(Parent_Table)和T2(Child_Table)
T1:
ID | LANG | ASSURANCE | VAL |
1 | L1 | ASSR1 | 0 |
1 | L2 | ASSR2 | 1 |
1 | L3 | ASSR3 | 5 |
T2:
ID | LANG | File | ASSURANCE | VAL |
1 | L1 | F1 | ASSR1 | 0 |
1 | L1 | F2 | ASSR1 | 4 |
1 | L2 | F3 | ASSR2 | 8 |
1 | L2 | F4 | ASSR2 | 3 |
1 | L3 | F5 | ASSR3 | 7 |
1 | L3 | F6 | ASSR3 | 0 |
預期輸出:
ID | File | ASSURANCE | VAL |
1 | L1 | ASSR1 | 0 | - Matched row from T1 for id=1 and lang=l1
1 | F1 | ASSR1 | 0 | - Matched row from T2 for id=1 and lang=l1
1 | F2 | ASSR1 | 4 | - Matched row from T2 for id=1 and lang=l1
1 | L2 | ASSR2 | 1 | - Matched row from T1 for id=1 and lang=l2
1 | F3 | ASSR2 | 8 | - Matched row from T2 for id=1 and lang=l2
1 | F4 | ASSR2 | 3 | - Matched row from T2 for id=1 and lang=l2
1 | L3 | ASSR3 | 5 | - Matched row from T1 for id=1 and lang=l3
1 | F5 | ASSR3 | 7 | - Matched row from T2 for id=1 and lang=l3
1 | F6 | ASSR3 | 0 | - Matched row from T2 for id=1 and lang=l3
需求:
我想遍歷T1以獲得id = 1,並且對於每個lang,我想首先輸出該行(來自T1),然后遍歷T2以獲得id和當前lang以及T2中的匹配記錄列表(對於id和current) lang),然后繼續處理T1中的下一個lang,直到在T1中處理了所有lang。
是否可以使用單個Oracle SQL查詢來實現?
謝謝。
嘗試這個:
with
T1 as (
select 1 as id, 'L1' as LANG, 'ASSR1' as assurance, 0 as VAL from dual union
select 1, 'L2', 'ASSR2',1 from dual union
select 1, 'L3','ASSR3',5 from dual),
T2 as (
select 1 as id , 'L1' as lang, 'F1' as "FILE", 'ASSR1' as assurance, 0 as val from dual union
select 1,'L1','F2','ASSR1',4 from dual union
select 1,'L2','F3','ASSR2',8 from dual union
select 1,'L2','F4','ASSR2',3 from dual union
select 1,'L3','F5','ASSR3',7 from dual union
select 1,'L3','F6','ASSR3',0 from dual),
T3 as (select t2.id, t2.lang, t2."FILE", t2.assurance, t2.val, row_number() over (partition by t2.id, t2.lang order by t2."FILE") as pos
from T2
inner join t1 on t1.id = t2.id and t1.lang = t2.lang)
select t1.id, t1.lang, t1.lang as "FILE", t1.assurance, t1.val, 0 as pos from T1
union
select t3.id, t3.lang, t3."FILE", t3.assurance, t3.val, t3.pos
from t3
order by id,lang,pos
輸出:
ID LANG FILE ASSURANCE VAL POS
1 L1 L1 ASSR1 0 0
1 L1 F1 ASSR1 0 1
1 L1 F2 ASSR1 4 2
1 L2 L2 ASSR2 1 0
1 L2 F3 ASSR2 8 1
1 L2 F4 ASSR2 3 2
1 L3 L3 ASSR3 5 0
1 L3 F5 ASSR3 7 1
1 L3 F6 ASSR3 0 2
使用union all
粘合表,添加有關行源的信息。 對於第一個表,還將列lang
添加為file_
。 最后對這個聯合進行排序。
select id, file_, assurance, val
from (
select id, lang, lang file_, assurance, val, 't1' source from t1 where id = 1
union all
select id, lang, file_, assurance, val, 't2' source from t2 where id = 1)
order by lang, source, file_
像這樣嗎
SQL> with t1 (id, lang, assurance, val) as
2 (select 1, 'L1', 'assr1', 0 from dual union all
3 select 1, 'L2', 'assr2', 1 from dual union all
4 select 1, 'L3', 'assr3', 5 from dual
5 ),
6 t2 (id, lang, cfile, assurance, val) as
7 (select 1, 'L1', 'F1', 'assr1', 0 from dual union all
8 select 1, 'L1', 'F2', 'assr1', 4 from dual union all
9 select 1, 'L2', 'F3', 'assr2', 8 from dual union all
10 select 1, 'L2', 'F4', 'assr2', 3 from dual union all
11 select 1, 'L3', 'F5', 'assr3', 7 from dual union all
12 select 1, 'L3', 'F6', 'assr3', 0 from dual
13 ),
14 inter as
15 (select t1.id, t1.lang, t1.lang cfile, t1.assurance, t1.val from t1
16 union all
17 select t2.id, t2.lang, t2.cfile, t2.assurance, t2.val from t2
18 )
19 select id, cfile, assurance, val
20 from inter
21 order by id, lang, cfile desc;
ID CF ASSUR VAL
---------- -- ----- ----------
1 L1 assr1 0
1 F2 assr1 4
1 F1 assr1 0
1 L2 assr2 1
1 F4 assr2 3
1 F3 assr2 8
1 L3 assr3 5
1 F6 assr3 0
1 F5 assr3 7
9 rows selected.
SQL>
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.