JS將字符串轉換為json對象

Question

需要將字符串轉換為json對象。

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json對象/字符串的規則：

1. 每次迭代加一。
2. split（'|'），這是json對象中的每一行。
3. split（'^'），這是行中的每個字段。
4. split（'〜'），這是字段中的每個子字段。
5. 需要考慮沒有子字段，字段或行
6. 需要在ES6之前的Internet Explorer 11中運行

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String Example:
var str = "1863707152859270^Exercise to lose weight^289169006^Reduce 20 pounds^Walk daily for one hour. Have a light dinner.^5/10/2013 12:00:00 AM^^1/21/2019 4:25:52 PM^Y^Frank the Tank^1/22/2019 8:50:02 AM^1/22/2019 8:50:02 AM^Frank the Tank^Abnormal LGSIL^1848065703239670^1863707006859070|1863707222859280^Exercise to lose weight^289169006^Reduce 20 pounds^Walk daily for one hour. Have a light dinner.^5/10/2013 12:00:00 AM^^1/21/2019 4:27:02 PM^Y^Frank the Tank^1/22/2019 8:50:02 AM^1/22/2019 8:50:02 AM^Frank the Tank^Abnormal LGSIL^1848065703239670^1863707006859070"

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嘗試：

  var str = "1863707152859270^Exercise to lose weight^289169006^Reduce 20 pounds^Walk daily for one hour. Have a light dinner.^5/10/2013 12:00:00 AM^^1/21/2019 4:25:52 PM^Y^Frank the Tank^1/22/2019 8:50:02 AM^1/22/2019 8:50:02 AM^Frank the Tank^Abnormal LGSIL^1848065703239670^1863707006859070|1863707222859280^Exercise to lose weight^289169006^Reduce 20 pounds^Walk daily for one hour. Have a light dinner.^5/10/2013 12:00:00 AM^^1/21/2019 4:27:02 PM^Y^Frank the Tank^1/22/2019 8:50:02 AM^1/22/2019 8:50:02 AM^Frank the Tank^Abnormal LGSIL^1848065703239670^1863707006859070" function ParseDelimList(str){ var result=[]; var rows = str.split('|'); var tmpString3 = []; for(var i=0;i<rows.length;i++){ var fields = rows[i].split('^'); var tmpString2 = []; for(var j=0;j<fields.length;j++){ var subfields = fields[j].split('~'); var tmpString1 = []; for(var l=0;l<subfields.length;l++){ var tmp1 = "{"+l+":"+subfields[l]+"}," tmpString1.push(tmp1); }; var tmp2 = "{"+j+":"+tmpString1[j]+"},"; tmpString2.push(tmp2); }; var tmp3 = "{"+i+":"+tmpString2[i]+"},"; tmpString3.push(tmp3); }; return tmpString3; }; console.log(ParseDelimList(str)) 

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最終結果（類似這樣）：

var json = [
  "1":{
    {"0":"1863707152859270"},
    {"1":"Exercise to lose weight"},
    {"2":"289169006"},
    {"3":"Reduce 20 pounds"},
    {"4":"Walk daily for one hour. Have a light dinner."},
    {"5":"5/10/2013 12:00:00 AM"},
    {"6":"1/21/2019 4:25:52 PM"},
    {"7":"Y"},
    {"8":"Frank the Tank"},
    {"9":"1/22/2019 8:50:02 AM"},
    {"10":"1/22/2019 8:50:02 AM"},
    {"11":"Frank the Tank"},
    {"12":"Abnormal LGSIL"},
    {"13":"1848065703239670"},
    {"14":"1863707006859070"},
  },
  "2":{
    {"0":"1863707152859270"},
    {"1":"Exercise to lose weight"},
    {"2":"289169006"},
    {"3":"Reduce 20 pounds"},
    {"4":"Walk daily for one hour. Have a light dinner."},
    {"5":"5/10/2013 12:00:00 AM"},
    {"6":"1/21/2019 4:25:52 PM"},
    {"7":"Y"},
    {"8":"Frank the Tank"},
    {"9":"1/22/2019 8:50:02 AM"},
    {"10":"1/22/2019 8:50:02 AM"},
    {"11":"Frank the Tank"},
    {"12":"Abnormal LGSIL"},
    {"13":"1848065703239670"},
    {"14":"1863707006859070"},
  }
];

Answer 1

到這里，准備成為JSON.stringify 。 三重split后再map即可到達：

 var str = "1863707152859270^Exercise to lose weight^289169006^Reduce 20 pounds^Walk daily for one hour. Have a light dinner.^5/10/2013 12:00:00 AM^^1/21/2019 4:25:52 PM^Y^Frank the Tank^1/22/2019 8:50:02 AM^1/22/2019 8:50:02 AM^Frank the Tank^Abnormal LGSIL^1848065703239670^1863707006859070|1863707222859280^Exercise to lose weight^289169006^Reduce 20 pounds^Walk daily for one hour. Have a light dinner.^5/10/2013 12:00:00 AM^^1/21/2019 4:27:02 PM^Y^Frank the Tank^1/22/2019 8:50:02 AM^1/22/2019 8:50:02 AM^Frank the Tank^Abnormal LGSIL^1848065703239670^1863707006859070"; var result = str.split('|').map(x => { return { row: x.split('^').map(y => { return { field: y.split('~').map(z => { return { subfield: z }; }) } }) } }); console.log(result); 

由於您的預期結果並不完全清楚，如果有任何遺漏，請告訴我。

編輯 ：添加了與下面的IE 11兼容的相同解決方案：

 var str = "1863707152859270^Exercise to lose weight^289169006^Reduce 20 pounds^Walk daily for one hour. Have a light dinner.^5/10/2013 12:00:00 AM^^1/21/2019 4:25:52 PM^Y^Frank the Tank^1/22/2019 8:50:02 AM^1/22/2019 8:50:02 AM^Frank the Tank^Abnormal LGSIL^1848065703239670^1863707006859070|1863707222859280^Exercise to lose weight^289169006^Reduce 20 pounds^Walk daily for one hour. Have a light dinner.^5/10/2013 12:00:00 AM^^1/21/2019 4:27:02 PM^Y^Frank the Tank^1/22/2019 8:50:02 AM^1/22/2019 8:50:02 AM^Frank the Tank^Abnormal LGSIL^1848065703239670^1863707006859070"; var result = str.split('|').map(function(x) { return { row: x.split('^').map(function(y) { return { field: y.split('~').map(function(z) { return { subfield: z }; }) } }) } }); console.log(result); 

Answer 2

建議：您實際上並不希望所有帶有key：value對的對象，而鍵只是索引。 如果僅具有數組（數組），則數據將更易於使用（並更好地反映源結構）。

var str = 'FOO^one|BAR|TEST^one^two^a$b$c^three';
var obj = str.split('|')
        .map(s => s.split('^')
            .map(x => x.split('$')));

console.log(JSON.stringify(obj));

Answer 3

您可以使用reduce split和map。

 var str = "1863707152859270^Exercise to lose weight^289169006^Reduce 20 pounds^Walk daily for one hour. Have a light dinner.^5/10/2013 12:00:00 AM^^1/21/2019 4:25:52 PM^Y^Frank the Tank^1/22/2019 8:50:02 AM^1/22/2019 8:50:02 AM^Frank the Tank^Abnormal LGSIL^1848065703239670^1863707006859070|1863707222859280^Exercise to lose weight^289169006^Reduce 20 pounds^Walk daily for one hour. Have a light dinner.^5/10/2013 12:00:00 AM^^1/21/2019 4:27:02 PM^Y^Frank the Tank^1/22/2019 8:50:02 AM^1/22/2019 8:50:02 AM^Frank the Tank^Abnormal LGSIL^1848065703239670^1863707006859070" function ParseDelimList(str){ return str.split(/[|]+/).reduce((op,inp,index)=>{ op[index]= inp .split(/[\\^]+/) .map((e,i)=>({[i]:e})) //change this if needed return op },{}) }; console.log(ParseDelimList(str)) 

我在提供的輸入中看不到~ ，因此未包含在答案中。

您只需在輸入中有~更改地圖即可。

.map((e,i)=>({[i]:e.split(/[~]+/).map((e,i)=>({[i]:e})}))