[英]Counting every word in a text file and outputting a cost
我的朋友確實寫佣金和每個單詞收費。 我想寫一個腳本,可以為他做計算。 我正在嘗試計算文本文件中的每個單詞。 它僅讀取第一行,而忽略其余的行。
我的python知識很少,但是我認為我走對了。 我認為我必須以某種方式使用readlines()每隔幾秒鍾重新讀取一次文件。
import math
import time
def count():
txt = input("What is your file name?\nNote: file must be in same location as script\n")
file = open(txt,"r")
word_list = file.read().split(',')
word_count = len(word_list)
words = word_count
file.close
return words
def output(items):
file = open("livecost.txt","w")
total = items * .02
file.write(format(total, ".2f"))
def main():
num = int()
print("Lanching script")
while num < 1000000:
output(count())
num = num + 1
time.sleep(1)
main()
想要的結果是使腳本在無限循環中運行,以重新檢查文本文件的字數計數,並輸出計算出的成本。 唯一的問題是弄清楚這一點。
這是為了數詞而笑:
def countwords(txtdir):
with open(txtdir) as f:
return len(f.read().split())
沒有輸出功能更好
def main(txtdir):
print("Lanching script")
with open("livecost.txt","w") as f:
for num in range(1000000):
f.write("{} \n".format(countwords(txtdir)))
time.sleep(1)
完整代碼:
import time,datetime
def countwords(txtdir):
with open(txtdir) as f:
return len(f.read().split())
def main(txtdir):
print("Lanching script")
with open("livecost.txt","w") as f:
for num in range(1000000):
f.write("{}\t{}\n".format(datetime.datetime.now(),countwords(txtdir)))
time.sleep(1)
main("What is your file name?\nNote: file must be in same location as script\n")
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