如何使用MySQL中的PHP中的按鈕刪除行

Question

我在從表中刪除行時遇到問題。 當我單擊“刪除”按鈕時，它確實將我帶到下一頁，並顯示“從播放器中刪除了0行”。 基本上，它可以正確執行，但是我無法刪除所選的行。 我已經能夠顯示並添加到表格中。

Player.php

<table id="table table-bordered">
<tr>
    <th>Id#</th>
    <th>Player(s)</th>
    <th>Position</th>
</tr>

if(!($stmt = $mysqli->prepare("SELECT id_Player, name_Player, position_Player FROM player s ORDER BY position_Player ASC"))){
echo "Prepare failed: "  . $mysqli->connect_errno . " " . $mysqli->connect_error;
}

if(!$stmt->execute())
{
echo "Execute failed: "  . $mysqli->connect_errno . " " . $mysqli->connect_error;
}
if(!$stmt->bind_result($id_Player, $name_Player, $position_Player))
{
 echo "Bind failed: "  . $mysqli->connect_errno . " " . $mysqli->connect_error;   
}

    while($stmt->fetch()){
    echo "<tr><td>  $id_Player </td> <td>  $name_Player </td><td>  $position_Player  </td>";

    ?>
        <td>
            <form id="delete" method="post" action="deletePlayers.php">

                <input type="submit" name="id_Player" value="Delete!"/>    

            </form>
        </td>
    </tr>

deletePlayers.php

if(!($stmt = $mysqli->prepare("DELETE FROM player WHERE id_Player  = ?"))){
    echo "Prepare failed: "  . $stmt->errno . " " . $stmt->error;}
if(!($stmt->bind_param("s",$_POST['id_Player']))){
    echo "Bind failed: "  . $stmt->errno . " " . $stmt->error;}
if(!$stmt->execute()){
    echo "Execute failed: "  . $stmt->errno . " " . $stmt->error;}     
else {
    echo "Removed " . $stmt->affected_rows . " row from player. <br/><br/><strong> Returning to 'Add Players'</strong>";}

Answer 1

問題在於這行代碼，

if(!($stmt->bind_param("s",$_POST['id_Player']))){}

這里$POST['id_player']是Delete! 因為您要在HTML代碼中傳遞輸入類型的名稱Submit，所以我認為您沒有任何等於Delete! id Delete! 在您的數據庫中。

解決方案

您需要做的是需要使用一個隱藏的輸入，該輸入將保存id_Player值，如下所示：

if(!($stmt = $mysqli->prepare("SELECT id_Player, name_Player, position_Player FROM player s ORDER BY position_Player ASC"))){
echo "Prepare failed: "  . $mysqli->connect_errno . " " . $mysqli->connect_error;
}

if(!$stmt->execute())
{
echo "Execute failed: "  . $mysqli->connect_errno . " " . $mysqli->connect_error;
}
if(!$stmt->bind_result($id_Player, $name_Player, $position_Player))
{
 echo "Bind failed: "  . $mysqli->connect_errno . " " . $mysqli->connect_error;   
}

    while($stmt->fetch()){
    echo "<tr><td>  $id_Player </td> <td>  $name_Player </td><td>  $position_Player  </td>";

    ?>
        <td>
            <form id="delete" method="post" action="deletePlayers.php">
                <input type="hidden" name="id_Player" value="<?= $id_Player ?>"/>
                <input type="submit" value="Delete!"/>    

            </form>
        </td>
    </tr>