使用 php mysql 將選定的值從 db 獲取到數據列表選項

Question

我需要從 db 中獲取選定的值到 datalist 框中。告訴我怎么做。 這是代碼。

<input list="Rank_Name" class="form-control" required>
                            <datalist id="Rank_Name">
                         <?php
                            $sel_cus = "select Rank_Name from ranks where Rank_Status=1";
                            $res_cus = mysqli_query($connection, $sel_cus);
                            while ($row = mysqli_fetch_array($res_cus)) {
                            ?>
                            <option value="<?php echo $row['Rank_Name'];?>"></option>
                           <?php
                            } 
                            ?>
                            </datalist>                   

Answer 1

如果我理解正確，您還需要在下拉列表中選擇具有其他值的值。 你可以通過這樣做來實現這一點

    <?php
    $select1="select Rank_Name from ranks where Rank_Status=1"; 
    $q=mysqli_query($select1) or die($select1);
    $row=mysqli_fetch_array($q); //here you are getting name of person whose rank is 1
    ?>

    <datalist id="Rank_Name">
     <?php 
            $s="select * from ranks ";
            $q=mysqli_query($s) or die($s);
            while($r=mysqli_fetch_array($q))
            { ?>
            <option value="<?php echo $r['Rank_Name']; ?>"<?php if($row['Rank_Name']==$r['Rank_Name']) echo 'selected="selected"'; ?>>
<?php echo $r['Rank_Name']; ?>
      </option>
            <?php } ?>
            </datalist>  

在上面的代碼中，這一行<?php if($row['Rank_Name']==$r['Rank_Name']) echo 'selected="selected"'; ?> <?php if($row['Rank_Name']==$r['Rank_Name']) echo 'selected="selected"'; ?>檢查第一次查詢的值是否相同，如果相同則該選項將被自動selected

Answer 2

<input list="Rank_Name" class="form-control" required>
                            <datalist id="Rank_Name">
                         <?php
                            $sel_cus = "select Rank_Name from ranks where Rank_Status=1";
                            $res_cus = mysqli_query($connection, $sel_cus);
                            while ($row = mysqli_fetch_array($res_cus)) {

                           echo "<option value=".$row['Rank_Name']."></option>";

                            } 
                            ?>
                            </datalist> 

試試這個代碼。 我在 while 循環中使用 echo <option>