[英]Addition of two binary numbers
我試圖通過將數字放入char數組來對每個數字進行補全,並使用if條件對每個數字進行補全。 應該覆蓋每個結果,並且應該將每個結果保存在String result
但是整個操作的結果始終為空白。 Java調試器無法正常工作,我不明白為什么它無法正常工作。
import java.util.Scanner;
public class BinaryAdder {
public static String add(String binary1, String binary2) {
String result = "";
char[] safea = binary1.toCharArray();
char[] safeb = binary2.toCharArray();
int lb1 = binary1.length() - 1;
int lb2 = binary2.length() - 1;
char reminder = 0;
while (lb1 != 0 || lb2 != 0) {
if (safea[lb1] == 0 && safeb[lb2] == 0 && reminder == 0) {
result += "0";
lb1--;
lb2--;
} else if (safea[lb1] == 1 && safeb[lb2] == 0 && reminder == 0) {
result += "1";
lb1--;
lb2--;
} else if (safea[lb1] == 1 && safeb[lb2] == 1 && reminder == 0) {
result += "0";
reminder = 1;
lb1--;
lb2--;
} else if (safea[lb1] == 1 && safeb[lb2] == 1 && reminder == 1) {
result += "1";
reminder = 1;
lb1--;
lb2--;
} else if (safea[lb1] == 1 && safeb[lb2] == 0 && reminder == 1) {
result += "0";
reminder = 1;
lb1--;
lb2--;
} else if (safea[lb1] == 0 && safeb[lb2] == 1 && reminder == 1) {
result += "0";
reminder = 1;
lb1--;
lb2--;
} else if (safea[lb1] == 0 && safeb[lb2] == 1 && reminder == 0) {
result += "1";
lb1--;
lb2--;
} else if (safea[lb1] == 0 && safeb[lb2] == 0 && reminder == 1) {
result += "1";
lb1--;
lb2--;
}
}
return result;
}
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.print("Summand: ");
String input1 = scan.next("(0|1)*");
System.out.print("Summand: ");
String input2 = scan.next("(0|1)*");
scan.close();
System.out.println("Result: " + add(input1, input2));
}
}
您可以使用Integer.parseInt(s, radix)
將這些位解析為整數。 您需要使用2的基數:
public static String add(String binary1, String binary2) {
int i1 = Integer.parseInt(binary1, 2);
int i2 = Integer.parseInt(binary2, 2);
return Integer.toBinaryString(i1 + i2);
}
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