[英]Unset array by key and value using PHP
我的數組是$ arrIncome和$ arrExpense。 他們有一些相同的日期,而有一些不相同的日期。
$arrIncome = [
[
'date' => '01-01-2019',
'total' => '500',
],
[
'date' => '02-01-2019',
'total' => '200',
],
[
'date' => '03-01-2019',
'total' => '300',
],
[
'date' => '04-01-2019',
'total' => '900',
],
];
$arrExpense= [
[
'date' => '01-01-2019',
'total' => '50',
],
[
'date' => '02-01-2019',
'total' => '60',
],
[
'date' => '07-01-2019',
'total' => '25',
],
[
'date' => '08-01-2019',
'total' => '50',
],
];
我循環$ arrIncome數組,如果我發現收入日期在$ arrExpense數組中,則將按收入日期$ arrIncome刪除$ arrExpense中的數組,因為我想創建唯一的日期。
foreach ($arrIncome as $income){
$isExistExpense = array_filter($arrExpense, function($expense) use($income){
return $expense->date == date('Y-m-d', strtotime($income->date));
});
if(count($isExistExpense) > 0 ){
foreach ($isExistExpense as $expense){
// THIS PLACE TO UNSET $arrExpense by date value
unset($arrExpense['date'] = $income->date); // this is a wrong way
}
}else{
// my code more here.....
}
}
您必須通過索引將其取消設置。
您可以這樣做:
// Get the intersection of the dates
$isExistExpense = array_intersect(
array_column($arrIncome,'date'),
array_column($arrExpense,'date'));
// Loop through the `$arrExpense` and unset the that exist in the array.
foreach($arrExpense as $index=>$vals){
if(in_array($vals['date'], $isExistExpense)){
unset($arrExpense[$index]);
}
}
希望這可以幫助,
您可以使用array_filter
直接刪除$arrExpense
中具有在$arrIncome
中存在的日期的元素(使用array_column
獲取該數組中的日期列表):
$arrExpense = array_filter($arrExpense, function ($v) use ($arrIncome) {
return !in_array($v['date'], array_column($arrIncome, 'date'));
});
print_r($arrExpense);
輸出:
Array (
[2] => Array ( [date] => 07-01-2019 [total] => 25 )
[3] => Array ( [date] => 08-01-2019 [total] => 50 )
)
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